The variance of temperatures (Fahrenheit) in Pittsburgh, Pa. is 340.57. What is this variance if temp is re-expressed in Celsius? [Hint: Conversion between Fahrenheit and Celsius is a linear transformation: Fahrenheit = Celsius*1.80 + 32, or Celsius = Fahrenheit*(1/1.80) - (32/1.80)]

The variance of temperatures (Fahrenheit) in Pittsburgh, Pa. is 340.57. What is this variance if temp is re-expressed in Celsius? [Hint: Conversion between Fahrenheit and Celsius is a linear transformation: Fahrenheit = Celsius1.80 + 32, or Celsius = Fahrenheit(1/1.80) - (32/1.80)]

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

The variance of temperatures (Fahrenheit) in Pittsburgh, Pa. is 340.57. What is this variance if temp is re-expressed in Celsius?

[Hint: Conversion between Fahrenheit and Celsius is a linear transformation:
Fahrenheit = Celsius*1.80 + 32, or
Celsius = Fahrenheit*(1/1.80) - (32/1.80)]

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