The vapour pressures of the pure components P and Q are 700 Torr and 500 Torr, respectively. When the two phases are in equilibrium at 1.0 atm, the mole fraction ofP in the liquid phase is 0.6 and in the vapour phase 0.4. The activity co-efficient of component P in the solution on the basis of Pouls's la
The vapour pressures of the pure components P and Q are 700 Torr and 500 Torr, respectively. When the two phases are in equilibrium at 1.0 atm, the mole fraction ofP in the liquid phase is 0.6 and in the vapour phase 0.4. The activity co-efficient of component P in the solution on the basis of Pouls's la
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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answer is 0.72. how is it arrived at? please show detailed steps and calculation.
![The vapour pressures of the pure components P and Q are 700 Torr and 500 Torr, respectively. When the
two phases are in equilibrium at 1.0 atm, the mole fraction of P in the liquid phase is 0.6 and in the vapour
phase 0.4. The activity co-efficient of component P in the solution on the basis of Raoult's law is
(a) 0.60
(b) 0.72
(d) 1.01
(c) 0.92](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6a4ef6a-cac9-4f46-ab1d-92c6d4784e63%2Ffe6ca9bf-15e9-4ee5-882c-a44521a0e035%2Ff76w0p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The vapour pressures of the pure components P and Q are 700 Torr and 500 Torr, respectively. When the
two phases are in equilibrium at 1.0 atm, the mole fraction of P in the liquid phase is 0.6 and in the vapour
phase 0.4. The activity co-efficient of component P in the solution on the basis of Raoult's law is
(a) 0.60
(b) 0.72
(d) 1.01
(c) 0.92
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