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In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s)+302(g) → 2Al2O3(s) What is the mass of 9.45 moles of Al 20 3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0₁ 9.45 moles Al2O3* 102.2 grams of Al, 0₂ = 0.0926 grams of Al2O3

In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s)+302(g) → 2Al2O3(s) What is the mass of 9.45 moles of Al 20 3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0₁ 9.45 moles Al2O3* 102.2 grams of Al, 0₂ = 0.0926 grams of Al2O3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Explain why this answer is incorrect based on what you know about dimensional analysis. Do not solve. Look at the calculation work and determine.

In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s) + 302(g) →2A/203(s) What is the mass of 9.45 moles of Al 203? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole AL, Q 9.45 moles Al₂O3× 102.2 grams of Al, 0, Is this answer correct? = 0.0926 grams of Al2O3
Transcribed Image Text:In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s) + 302(g) →2A/203(s) What is the mass of 9.45 moles of Al 203? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole AL, Q 9.45 moles Al₂O3× 102.2 grams of Al, 0, Is this answer correct? = 0.0926 grams of Al2O3
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