### Calculating the Vapor Pressure of a SolutionThe vapor pressure of **benzene** is **73.03 mm Hg** at **25 °C**. A nonvolatile, nonelectrolyte that dissolves in benzene is **cholesterol**.Calculate the vapor pressure of the solution at **25 °C** when **10.28 grams** of **cholesterol**, **C₇₂H₄₆O (386.6 g/mol)**, are dissolved in **268.4 grams** of **benzene**.#### Given Data:- **Benzene** (C₆H₆): **78.12 g/mol**- **Vapor pressure of pure benzene**: **73.03 mm Hg**- **Mass of cholesterol (C₂₇H₄₆O)**: **10.28 grams** - **Molar mass of cholesterol**: **386.6 g/mol**- **Mass of benzene**: **268.4 grams**#### Formula to Calculate:\[ \text{VP(solution)} = \square \text{ mm Hg} \]To solve the problem, use the data given and the appropriate equations related to vapor pressure lowering due to a solute.### Steps to Solve:1. **Calculate the moles of Benzene (C₆H₆)**:\[ \text{Moles of Benzene} = \frac{\text{mass}}{\text{molar mass}} = \frac{268.4 \, \text{g}}{78.12 \, \text{g/mol}} \]2. **Calculate the moles of Cholesterol (C₂₇H₄₆O)**:\[ \text{Moles of Cholesterol} = \frac{10.28 \, \text{g}}{386.6 \, \text{g/mol}} \]3. **Calculate the mole fraction of Benzene**: - The mole fraction of the solvent (benzene) can be determined by finding the total moles of the solution and using the formula:\[ \text{Mole fraction of Benzene} = \frac{\text{Moles of Benzene}}{\text{Moles of Benzene} + \text{Moles of Cholesterol}} \]4. **Calculate the Vapor Pressure of the Solution**: - Use Raoult’s

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The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is cholesterol. Calculate the vapor pressure of the solution at 25 °C when 10.28 grams of cholesterol, C27H460 (386.6 g/mol), are dissolved in 268.4 grams of benzene. benzene = C,H = 78.12 g/mol. VP(solution) = mm Hg

The vapor pressure of benzene is 73.03 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in benzene is cholesterol. Calculate the vapor pressure of the solution at 25 °C when 10.28 grams of cholesterol, C27H460 (386.6 g/mol), are dissolved in 268.4 grams of benzene. benzene = C,H = 78.12 g/mol. VP(solution) = mm Hg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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