The values of the ideal gas constant (R) are given in the following table: Values of the Universal Gas Constant R = 8.314 J-mol--K¯' = 8.314 m³-Pa-mol.K-! = 83.14 cm³-bar-mol¬-K¯1 = 8314 cm³ -kPa-mol'K^! 82.06 cm³-(atm)-mol'K¯l = 62, 356 cm³-(torr)-molK" = 1.987 (cal)-mol¬-K' = 1.986 (Btu)(lb mole)¯'(R)~1 = 0.7302 (ft)³ (atm) (lb mol)¯'(R)~' = 10.73 (ft) (psia) (lb mol)¯'(R)~1 1545 (ft) (lbf) (lb mol)¯'(R)¯1 %3D %3D Calculate compressibility (Z) and the molar volume (V) for nitrogen trifluoride for the following condition. (For nitrogen trifluoride, Tc= 234 K, Pc = 44.6 bar, and w = 0.126.) Consider nitrogen trifluoride at 300 K and 95 bar and use the Peng/Robinson equation. The molar volume is cm3.mol"1. The compressibility is
The values of the ideal gas constant (R) are given in the following table: Values of the Universal Gas Constant R = 8.314 J-mol--K¯' = 8.314 m³-Pa-mol.K-! = 83.14 cm³-bar-mol¬-K¯1 = 8314 cm³ -kPa-mol'K^! 82.06 cm³-(atm)-mol'K¯l = 62, 356 cm³-(torr)-molK" = 1.987 (cal)-mol¬-K' = 1.986 (Btu)(lb mole)¯'(R)~1 = 0.7302 (ft)³ (atm) (lb mol)¯'(R)~' = 10.73 (ft) (psia) (lb mol)¯'(R)~1 1545 (ft) (lbf) (lb mol)¯'(R)¯1 %3D %3D Calculate compressibility (Z) and the molar volume (V) for nitrogen trifluoride for the following condition. (For nitrogen trifluoride, Tc= 234 K, Pc = 44.6 bar, and w = 0.126.) Consider nitrogen trifluoride at 300 K and 95 bar and use the Peng/Robinson equation. The molar volume is cm3.mol"1. The compressibility is
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
The molar volume is cm3·mol-1.
The compressibility is .
Transcribed Image Text:Values of the Universal Gas Constant
R =
8.314 J-mol--K-' = 8.314 m³.Pa-mol¬1·K-'
83.14 cm3-bar-mol¬1-K- = 8314 cm³ -kPa-mol-1.K-1
82.06 cm³-(atm)-mol K-1 = 62, 356 cm³-(torr)-mol¯1-K-1
1.987 (cal)-mol K'=1.986 (Btu)(lb mole) (R)
= 0.7302 (ft) (atm) (lb mol) (R)-1 = 10.73 (ft) (psia) (lb mol) (R)-1
= 1545 (ft) (lbf) (lb mol)¯(R)¯
Calculate compressibility (Z) and the molar volume (V) for nitrogen trifluoride for the following condition. (For nitrogen
trifluoride, Tc= 234 K, Pc= 44.6 bar, and w = 0.126.)
Consider nitrogen trifluoride at 300 K and 95 bar and use the Soave/Redlich/Kwong equation. (You must provide an answer before
moving to the next part.)
The molar volume is 188.56
cm3.mol1.
The compressibility is 0.7182
Transcribed Image Text:The values of the ideal gas constant (R) are given in the following table:
Values of the UniverSal Gas Constant
R = 8.314 J-mol¬1-K¯1 = 8.314 m³-Pa-mol-'-K-'
= 83.14 cm³-bar-mol-1-K-1 = 8314 cm3 -kPa-mol¬1-K-1
= 82.06 cm³ (atm)-mol1 K- = 62, 356 cm³.(torr)-mol1.K-
1.987 (cal)-mol.-K1 = 1.986 (Btu)(lb mole) (R)-
= 0.7302 (ft)° (atm) (lb mol)~'(R)~1 = 10.73 (ft)° (psia) (lb mol)- (R)-1
1545 (ft) (lbf) (lb mol)¯(R)~1
Calculate compressibility (Z) and the molar volume (V) for nitrogen trifluoride for the following condition. (For nitrogen
trifluoride, Tc= 234 K, Pc= 44.6 bar, and w = 0.126.)
Consider nitrogen trifluoride at 300 K and 95 bar and use the Peng/Robinson equation.
The molar volume is
cm3.mol1.
The compressibility is
Expert Solution
Step 1
In thermodynamics, compressibility is a measure of the relative volume change of a fluid or solid as a response to a pressure change. It is denoted by Z.
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