The value of Kc at a given temperature is 2500 for the decomposition of hydrazine: N2H4(g) > 2 H2(g) + N2(g) Which statements regarding this reaction and its reverse reaction are true? Select all that apply. I. The forward reaction is reactant favored at equilibrium. II. The forward reaction is product favored at equilibrium. III. The reverse reaction is reactant favored when the rate of the forward reaction equals the rate of the reverse reaction. II
The value of Kc at a given temperature is 2500 for the decomposition of hydrazine: N2H4(g) > 2 H2(g) + N2(g) Which statements regarding this reaction and its reverse reaction are true? Select all that apply. I. The forward reaction is reactant favored at equilibrium. II. The forward reaction is product favored at equilibrium. III. The reverse reaction is reactant favored when the rate of the forward reaction equals the rate of the reverse reaction. II
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Constant and Reaction Dynamics**
The value of \( K_c \) at a given temperature is 2500 for the decomposition of hydrazine:
\[ \text{N}_2\text{H}_4(g) \leftrightarrow 2 \text{H}_2(g) + \text{N}_2(g) \]
**Which statements regarding this reaction and its reverse reaction are true? Select all that apply.**
I. The forward reaction is reactant favored at equilibrium.
II. The forward reaction is product favored at equilibrium.
III. The reverse reaction is reactant favored when the rate of the forward reaction equals the rate of the reverse reaction.
**Selected Answer:**
- III
**Explanation:**
Given that \( K_c = 2500 \), the forward reaction is significantly product favored at equilibrium, as a large \( K_c \) value indicates that products predominate.
- Statement I is false because the reaction is not reactant favored at equilibrium.
- Statement II is false because even though the forward reaction is product favored at equilibrium, the statement doesn't align with the equilibrium conditions.
- Statement III is true because it explains the condition where equilibrium is reached, meaning the rates of the forward and reverse reactions are equal.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ce5f382-c21d-48ef-8c6b-42079a16ed57%2F6d7c8fe0-09f3-4bc8-8a06-19dc62a57a5b%2Ftp5c84n_processed.png&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constant and Reaction Dynamics**
The value of \( K_c \) at a given temperature is 2500 for the decomposition of hydrazine:
\[ \text{N}_2\text{H}_4(g) \leftrightarrow 2 \text{H}_2(g) + \text{N}_2(g) \]
**Which statements regarding this reaction and its reverse reaction are true? Select all that apply.**
I. The forward reaction is reactant favored at equilibrium.
II. The forward reaction is product favored at equilibrium.
III. The reverse reaction is reactant favored when the rate of the forward reaction equals the rate of the reverse reaction.
**Selected Answer:**
- III
**Explanation:**
Given that \( K_c = 2500 \), the forward reaction is significantly product favored at equilibrium, as a large \( K_c \) value indicates that products predominate.
- Statement I is false because the reaction is not reactant favored at equilibrium.
- Statement II is false because even though the forward reaction is product favored at equilibrium, the statement doesn't align with the equilibrium conditions.
- Statement III is true because it explains the condition where equilibrium is reached, meaning the rates of the forward and reverse reactions are equal.
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