The frequencies of notes form a geometric sequence with a common ratio 2 1/12. Write an explicit formula giving the frequency an of a note n notes higher than A-440. The unit hertz (abbreviated Hz) describes the number of cycles per second that occur for repeating behaviors. For example, the frequency ofmusical notes are measured in hertz because sound is formed by changes in air pressure caused by vibrations. If a note's frequency is 220 Hz itmeans that the note causes changes in air pressure that repeat 220 times per second. Higher frequency notes are perceived as having a higherpitch by humans (treble) and lower frequency notes are perceived as having a lower pitch (bass). The note A-440 (also called "Concert A") isoften used as the baseline note for tuning instruments and has a frequency of 440 Hz.a. The frequencies of notes form a geometric sequence with a common ratio 2. Write an explicit formula giving the frequency a, of a noten notes higher than A-440. (Note: the notes are labeled, in order, as A, Bb, B, C, C#, D, Eb, E, F, F#, G, and G#. After G# the note namesreрeat.)Previewb. An octave describes the interval between two notes such that the frequency of the higher note is twice that of the lower note. How manynotes above A-440 must we go to reach a change of one octave?notesPreview

(a) Geometric series (nthterm ) is given as,tn=arn-1where a=first term=440 Hzr=common ratio=21/12the…

Answered: The unit hertz (abbreviated Hz)…

Similar questions

The string of 5 meters long is clamped at the ends and is vibrating as the fifth harmonic. The string vibrates up and down with 80 complete vibrational cycles in 6 seconds. Determine the speed for this wave.
A metal has an atomic weight of 56.3, density of 8.9 x 10 3 Kg/m3, frequency of longitudinal and transverse modes are 5.76 x 10 3 m/s and 3.22 x 103 m/s. Estimate the specific heat of the metal at 30 K and 50 K.
The frequency of first overtone of an open pipe is 300Hz, What is the fundamental frequency?
Two strings both vibrate at exactly 903 Hz. The tension in one of them is then decreased slightly. As a result, 6 beats per second are heard when both strings vibrate. What is the new frequency of the string that was loosen? Calculate to one decimal.
Hello, based on page 1 can you do ONLY question number 5 (on page 2)
The wavelength of light visible to the human eye is on the order of 6 × 10 −7 m. If the speed of light in air is 3 × 10 8 m/s, find the frequency of the lightwave.
A periodic vibration at x = 0, t = 0 displaces air molecules along the x direction by smax = 3.2E-05 m. The motion produces a sound wave that travels at a velocity of v = 336 m/s with a frequency of f = 120 Hz. Take the density of air as ρa = 1.20 kg/m3. Calculate the wavelength λ of the sound wave, in meters. Calculate the wavenumber k of the sound, in radians per meter. Calculate the angular frequency of the sound ω, in radians per second.
The string of 5 meters long is clamped at the ends and is vibrating as the third harmonic. The string vibrates up and down with 53 complete vibrational cycles in 9 seconds. Determine the frequency of the wave.
Use dimensional analysis to find how the speed vvv of a wave on a string of circular cross section depends on the tension in the string, T, the radius of the string, R, and its mass per volume, ρ (rho). Express your answer in terms of the variables T, R, and ρ(rho).
The lowest A on a piano has a frequency of 27.5 Hz. Assume: The tension in the A piano wire (of length 0.51 m) is 305 N, and one-half wavelength occupies the wire. What is the mass of m the wire? Answer in units of kg.
The string of 5 meters long is clamped at the ends and is vibrating as the third harmonic. The string vibrates up and down with 75 complete vibrational cycles in 6 seconds. Determine the frequency of the wave.
What is the frequency observed with a wavelengh of (6.1x10^2) nm? Answer with 2 significant figures and it must be in scientific notation. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Answer x10

SEE MORE QUESTIONS