The union for a particular industry has determined that the standard deviation of the daily wages of its workers is $25. A random sample of 100 workers in this ndustry has a mean daily wage of $110. Find a 99% confidence interval for the true mean daily wage of all union workers in the industry. Then give its lower imit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: || ? Upper limit:

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The union for a particular industry has determined that the standard deviation of the daily wages of its workers is $25. A random sample of 100 workers in this
industry has a mean daily wage of $110. Find a 99% confidence interval for the true mean daily wage of all union workers in the industry. Then give its lower
limit and upper limit.
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)
Lower limit: ||
?
Upper limit:|
Transcribed Image Text:The union for a particular industry has determined that the standard deviation of the daily wages of its workers is $25. A random sample of 100 workers in this industry has a mean daily wage of $110. Find a 99% confidence interval for the true mean daily wage of all union workers in the industry. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: || ? Upper limit:|
Expert Solution
Step 1

Given,

σ = 25

n = 100

x- = 110

confidence coefficient = α2Z = 2.576

confidence interval = x- ±  α2Z . σn

margin of error =  α2Z  .   σn

α2Z = 2.576         ( for 99% confidence interval )

 

 

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