The two spheres of equal mass m are able to slide along the horizontal rotating rod. If they are initially latched in position a distance r from the rotating axis with the assembly rotating freely with an angular velocity wo, determine the new angular velocity w after the spheres are released and finally assume positions at the ends of the rod at a radial distance of d = 2.8r. Also find the fraction n of the initial kinetic energy of the system which is lost. Neglect the small mass of the rod and shaft. Answers: W = n= m i i ale m Wo

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The two spheres of equal mass m are able to slide along the horizontal rotating rod. If they are initially latched in position a distance r
from the rotating axis with the assembly rotating freely with an angular velocity wo, determine the new angular velocity w after the
spheres are released and finally assume positions at the ends of the rod at a radial distance of d = 2.8r. Also find the fraction n of the
initial kinetic energy of the system which is lost. Neglect the small mass of the rod and shaft.
Answers:
W =
n=
711
i
i
ale
m
Wo
Transcribed Image Text:The two spheres of equal mass m are able to slide along the horizontal rotating rod. If they are initially latched in position a distance r from the rotating axis with the assembly rotating freely with an angular velocity wo, determine the new angular velocity w after the spheres are released and finally assume positions at the ends of the rod at a radial distance of d = 2.8r. Also find the fraction n of the initial kinetic energy of the system which is lost. Neglect the small mass of the rod and shaft. Answers: W = n= 711 i i ale m Wo
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