The two reactants shown below are combined to bring about a nucleophilic substitution reaction. CH₂C=CNa + CH3CH₂CH₂Br f. HBr g. CH₂=CH₂ h. CH3C=C i. Br j. Na+ k. CH3C=CH I. none Which letter designates the electrophilic carbon at which substitution occurs? (If no reaction occurs enter the letter corresponding to "none.") Which letter corresponds to the leaving group? Which letter designates the nucleophile?
The two reactants shown below are combined to bring about a nucleophilic substitution reaction. CH₂C=CNa + CH3CH₂CH₂Br f. HBr g. CH₂=CH₂ h. CH3C=C i. Br j. Na+ k. CH3C=CH I. none Which letter designates the electrophilic carbon at which substitution occurs? (If no reaction occurs enter the letter corresponding to "none.") Which letter corresponds to the leaving group? Which letter designates the nucleophile?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![The two reactants shown below are combined to bring about a nucleophilic substitution reaction.
\[ \text{C}\text{H}_3\text{C}\equiv\text{CNa} \,\,\,+\,\,\, \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} \longrightarrow \]
Labels for atoms and groups within the molecules:
- \( \text{a.} \)
- \( \text{b.} \)
- \( \text{c.} \) C
- \( \text{d.} \) C
- \( \text{e.} \) C
Possible answers:
- \( \text{f.} \) HBr
- \( \text{g.} \) CH₂=CH₂
- \( \text{h.} \) CH₃C≡C⁻
- \( \text{i.} \) Br⁻
- \( \text{j.} \) Na⁺
- \( \text{k.} \) CH₃C≡CH
- \( \text{l.} \) none
Questions:
1. Which letter designates the electrophilic carbon at which substitution occurs? (If no reaction occurs enter the letter corresponding to "none.")
2. Which letter corresponds to the leaving group?
3. Which letter designates the nucleophile?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb41c431a-d537-4c9f-b640-b49be1be5173%2F6bb48af1-b5e2-4667-9562-a8e4434e0357%2Fx9w3ixk_processed.png&w=3840&q=75)
Transcribed Image Text:The two reactants shown below are combined to bring about a nucleophilic substitution reaction.
\[ \text{C}\text{H}_3\text{C}\equiv\text{CNa} \,\,\,+\,\,\, \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} \longrightarrow \]
Labels for atoms and groups within the molecules:
- \( \text{a.} \)
- \( \text{b.} \)
- \( \text{c.} \) C
- \( \text{d.} \) C
- \( \text{e.} \) C
Possible answers:
- \( \text{f.} \) HBr
- \( \text{g.} \) CH₂=CH₂
- \( \text{h.} \) CH₃C≡C⁻
- \( \text{i.} \) Br⁻
- \( \text{j.} \) Na⁺
- \( \text{k.} \) CH₃C≡CH
- \( \text{l.} \) none
Questions:
1. Which letter designates the electrophilic carbon at which substitution occurs? (If no reaction occurs enter the letter corresponding to "none.")
2. Which letter corresponds to the leaving group?
3. Which letter designates the nucleophile?
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