The two metal objects in the figure have net charges of +74 pc and -74 pC, which result in a 23 V potential difference between them. (a) What is the capacitance of the system? (b) If the charges are changed to +210 pC and -210 pC, what does the capacitance become? (c) What does the potential difference become? (a) Number i (b) Number i (c) Number i Units Units Units

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter8: Capacitance
Section: Chapter Questions
Problem 8.6CYU: Check Your Understanding The potential difference across a 5.0-pF capacitor is 0.40 V. (a) What is...
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The two metal objects in the figure have net charges
of +74 pC and -74 pC, which result in a 23 V
potential difference between them. (a) What is the
capacitance of the system? (b) If the charges are
changed to +210 pC and -210 pC, what does the
capacitance become? (c) What does the potential
difference become?
(a) Number
i
(b) Number i
(c) Number
i
Units
Units
Units
<>
Transcribed Image Text:The two metal objects in the figure have net charges of +74 pC and -74 pC, which result in a 23 V potential difference between them. (a) What is the capacitance of the system? (b) If the charges are changed to +210 pC and -210 pC, what does the capacitance become? (c) What does the potential difference become? (a) Number i (b) Number i (c) Number i Units Units Units <>
Expert Solution
Step 1: Charge and capacitance

a)

Write the expression for the charge and substitute the corresponding values to calculate the capacitance of the system.

table row cell Q equals C V end cell row cell 74 text  pC end text equals C left parenthesis 23 text  V end text right parenthesis end cell row cell C equals 3.217 text  pF end text end cell end table

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