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The two loads shown in (Figure 1) can be described as ollows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an mpedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 N j0.05 2 L2 Find the rms value of the source voltage. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – Ov,)/w, where Oy, and Ov, are the phase angles of the voltages VI, and Vg respectively, and w is the angular frequency of the voltages. Does the load voltage lead or lag the source voltage?

The two loads shown in (Figure 1) can be described as ollows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an mpedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 N j0.05 2 L2 Find the rms value of the source voltage. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – Ov,)/w, where Oy, and Ov, are the phase angles of the voltages VI, and Vg respectively, and w is the angular frequency of the voltages. Does the load voltage lead or lag the source voltage?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The two loads shown in (Figure 1) can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an impedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 0 j0.05 N L2 а. Find the rms value of the source voltage. b. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – bv,)/w, where Oy, and Ov, are the phase angles of the voltages VI and V, respectively, and w is the angular frequency of the voltages. с. Does the load voltage lead or lag the source voltage?
Transcribed Image Text:The two loads shown in (Figure 1) can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 KVAR of reactive power; load 2 has an impedance of (60 + j80) N. The voltage at the terminals of the loads is 1500/2 cos(100rt) V. 0.5 0 j0.05 N L2 а. Find the rms value of the source voltage. b. Determine by how much time the load voltage is out of phase with the source voltage by finding the value of (Ov, – bv,)/w, where Oy, and Ov, are the phase angles of the voltages VI and V, respectively, and w is the angular frequency of the voltages. с. Does the load voltage lead or lag the source voltage?
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