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The two loads shown in Fig. P10.21 can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 kVAR of reactive power; Load 2 has an impedance of (60 + j80) . The voltage at the terminals of the loads is 1000V/2 cos 100mt V. a) Find the rms value of the source voltage. b) By how many microseconds is the load voltage out of phase with the source voltage? c) Does the load voltage lead or lag the source voltage?

The two loads shown in Fig. P10.21 can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 kVAR of reactive power; Load 2 has an impedance of (60 + j80) . The voltage at the terminals of the loads is 1000V/2 cos 100mt V. a) Find the rms value of the source voltage. b) By how many microseconds is the load voltage out of phase with the source voltage? c) Does the load voltage lead or lag the source voltage?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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10.21 The two loads shown in Fig. P10.21 can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 kVAR of reactive power; Load 2 has an impedance of (60+ j80) 2. The voltage at the terminals of the loads is 1000√2 cos 100mt V. a) Find the rms value of the source voltage. b) By how many microseconds is the load voltage out of phase with the source voltage? c) Does the load voltage lead or lag the source voltage? Figure P10.21 + 0.5 Ω j0.05 Ω V₁ L₁ L2
Transcribed Image Text:10.21 The two loads shown in Fig. P10.21 can be described as follows: Load 1 absorbs an average power of 10 kW and delivers 4 kVAR of reactive power; Load 2 has an impedance of (60+ j80) 2. The voltage at the terminals of the loads is 1000√2 cos 100mt V. a) Find the rms value of the source voltage. b) By how many microseconds is the load voltage out of phase with the source voltage? c) Does the load voltage lead or lag the source voltage? Figure P10.21 + 0.5 Ω j0.05 Ω V₁ L₁ L2
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