The two arcs (quarter circles) shown in the figure below has their center at O. If R₁ < R₂ and I₁ > I2. The direction of the magnetic field at point O is: 1₂ X + Z - Z ➜X R₁ 1₁ > 12 O The given in not sufficient O The magnetic field is zero None of the above R₂
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- At the equator, near the surface of Earth, the magnetic field is approximately 65.0 ?T northward and the electric field is about 300 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron with instantaneous velocity of 6.00 106 m/s directed to the east in this environment. gravitational N electric N magnetic N04 The closed loop shown in the figure below carries a current 4 A in the clockwise direction. The loop consists of two arcs of radii a =7 cm and b= 12 cm that are connected by straight segments and the point Pis at the center of both arcs. y a P The direction of the magnetic field due to the straight segment at point P is: OInto the page OOut of the page ONo field F. 2. (5 points) The magnitude of the magnetic field due to the straiyht segments at point P is: The direction of the magnetic field due to the inner is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the inner arc at point P is: The direction of the magnetic field due to the outer arc at point P is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the outer arc at point Pis: Calculate the net magnetic field vector at point P. Bret =<The uniform 30.0 mT magnetic field in the figure points in the positive z-direction. An electron enters the region of magnetic field with a speed of 5.50 x 106 m/s and at an angle of 30° above the xy-plane. (Figure 1) Figure X Z 000 30° 12 1 of 1 Part A Find the radius r of the electron's spiral trajectory. Express your answer with the appropriate units. I JA Value Submit Part B DO Request Answer Find the pitch p of the electron's spiral trajectory. Express your answer with the appropriate units. μÅ Value Units Submit Request Answer Return to Assignment Units www ? Provide Feedback ?
- Figure below shows two long straight wires separated by the distance d = 1.0 m. The current in the left-hand wire is I, = 6.0 A in the upward direction. If the magnetic field at point P is zero, the magnitude and direction of the current I, in the right-hand wire is: %3D -p- a. 1.5 A, upward Ob. 4.5 A, upward O c. 3.0 A, downward O d. 1.5 A, downward e. 3.0 A, upwardAn electron is moving to the right when suddenly a magnetic field is switched on that points out of the page. Describe the resulting path of the electron. O a clockwise circle in the plane of the page O a circular path coming out of the page on the right and into the page on the left O a counterclockwise circle in the plane of the page O a straight line O a circular path coming out of the page on the left and into the page on the rightA flat copper ribbon 0.330 mm thick carries a steady current of 44.0 A and is located in a uniform 1.80 T magnetic field directed perpendicular to the plane of the ribbon. If a Hall voltage of 9.60 μV is measured across the ribbon, what is the charge density of the free electrons? m-³ What effective number of free electrons per atom does this result indicate?
- Two long, parallel wires carry currents of I, = 10.0 A and I, = 5.0 A in opposite directions (see figure below). Which of the following statements must be true? More than one statement may be correct. I II III O In region I, the magnetic field is into the page and is never zero. O In region II, the field is into the page and can be zero. O In region III, it is possible for the field to be zero. O In region I, the magnetic field is out of the page and is never zero. O There are no points where the field is zero.04 The closed loop shown in the figure below carries a current 4 A in the clockwise direction. The loop consists of two arcs of radii a =7 cm and b= 12 cm that are connected by straight segments and the point P is at the center of both arcs. y a P The direction of the magnetic field due to the straight segment at point P is: OInto the page OOut of the page ONo field F. The magnitude of the magnetic field due to the straiyht segments at point P is: The direction of the magnetic field due to the inner is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the inner arc at point P is: The direction of the magnetic field due to the outer arc at point P is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the outer arc at point Pis: Calculate the net magnetic field vector at point P. Bnet =<