04The closed loop shown in the figure below carries acurrent 4 A in the clockwise direction. The loop consists of two arcs of radiia =7 cm and b= 12 cm that are connected by straight segments and thepoint Pis at the center of both arcs.yaPThe direction of the magnetic field due to the straight segment atpoint P is:OInto the pageOOut of the pageONo fieldF.2. (5 points) The magnitude of the magnetic field due to the straiyhtsegments at point P is:The direction of the magnetic field due to the inneris:OInto the pageOOut of the pageONo fieldThe magnitude of the magnetic field due to the inner arc at pointP is:The direction of the magnetic field due to the outer arc at point Pis:OInto the pageOOut of the pageONo fieldThe magnitude of the magnetic field due to the outer arc at pointPis:Calculate the net magnetic field vector at point P.Bret =<

The magnetic field at a point on the axis of a straight current carrying conductor is zero because…

The closed loop shown in the figure below carries a current 4 A in the clockwise direction. The loop consists of two arcs of radii a =7 cm and b= 12 cm that are connected by straight segments and the point P is at the center of both arcs. a P The direction of the magnetic field due to the straight segment at point P is: Olnto the page COut of the page ONo field 2. (5 points) The magnitude of the magnetic field due to the strakyht segments at point P is: The direction of the magnetic field due to the inner is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the inner arc at point Pis: The direction of the magnetic field due to the outer arc at point P is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the outer arc at point Pis: Calculate the net magnetic field vector at point P. Bnet =<

The closed loop shown in the figure below carries a current 4 A in the clockwise direction. The loop consists of two arcs of radii a =7 cm and b= 12 cm that are connected by straight segments and the point P is at the center of both arcs. a P The direction of the magnetic field due to the straight segment at point P is: Olnto the page COut of the page ONo field 2. (5 points) The magnitude of the magnetic field due to the strakyht segments at point P is: The direction of the magnetic field due to the inner is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the inner arc at point Pis: The direction of the magnetic field due to the outer arc at point P is: OInto the page OOut of the page ONo field The magnitude of the magnetic field due to the outer arc at point Pis: Calculate the net magnetic field vector at point P. Bnet =<

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

04
The closed loop shown in the figure below carries a
current 4 A in the clockwise direction. The loop consists of two arcs of radii
a =7 cm and b= 12 cm that are connected by straight segments and the
point Pis at the center of both arcs.
y
a
P
The direction of the magnetic field due to the straight segment at
point P is:
OInto the page
OOut of the page
ONo field
F.
2. (5 points) The magnitude of the magnetic field due to the straiyht
segments at point P is:
The direction of the magnetic field due to the inner
is:
OInto the page
OOut of the page
ONo field
The magnitude of the magnetic field due to the inner arc at point
P is:
The direction of the magnetic field due to the outer arc at point P
is:
OInto the page
OOut of the page
ONo field
The magnitude of the magnetic field due to the outer arc at point
Pis:
Calculate the net magnetic field vector at point P.
Bret =<

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