The turd is launched at a speed of 46 m/s at an angle of 48 degrees above the horizontal. How far horizontally from the catapult should a portal be placed in order to intercept the turd before it hits the ground?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Certainly! Here is a transcription and explanation of the text suitable for an educational website.

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## Projectile Motion Problem

**Scenario:**

An object is launched at a speed of 46 m/s at an angle of 48 degrees above the horizontal. The question is to determine how far horizontally from the catapult a portal should be placed in order to intercept the object before it hits the ground.

**Key Concepts:**

1. **Initial Velocity (v₀):** 46 m/s
2. **Launch Angle:** 48 degrees above the horizontal
3. **Horizontal Range (R):** The horizontal distance traveled by the object. This is what we aim to calculate.

**Steps to Solve:**

1. **Resolve Initial Velocity:**
   - Horizontal Component (v₀x): \( v₀ \times \cos(\theta) \)
   - Vertical Component (v₀y): \( v₀ \times \sin(\theta) \)

2. **Time of Flight (T):**
   - Use the formula for vertical motion \( T = \frac{2 \times v₀y}{g} \)
   - Here, g is the acceleration due to gravity (approximately \( 9.81 \, m/s² \)).

3. **Calculate Horizontal Range (R):**
   - \( R = v₀x \times T \)

**Diagrams or Calculations:**

(As the original image is text-based, create diagrams showing the projectile’s trajectory, the breakdown of the initial velocity into components, and the calculation steps.)

Using these steps, you can determine the horizontal distance necessary for placing the portal. This application demonstrates fundamental principles of physics involving projectile motion.
Transcribed Image Text:Certainly! Here is a transcription and explanation of the text suitable for an educational website. --- ## Projectile Motion Problem **Scenario:** An object is launched at a speed of 46 m/s at an angle of 48 degrees above the horizontal. The question is to determine how far horizontally from the catapult a portal should be placed in order to intercept the object before it hits the ground. **Key Concepts:** 1. **Initial Velocity (v₀):** 46 m/s 2. **Launch Angle:** 48 degrees above the horizontal 3. **Horizontal Range (R):** The horizontal distance traveled by the object. This is what we aim to calculate. **Steps to Solve:** 1. **Resolve Initial Velocity:** - Horizontal Component (v₀x): \( v₀ \times \cos(\theta) \) - Vertical Component (v₀y): \( v₀ \times \sin(\theta) \) 2. **Time of Flight (T):** - Use the formula for vertical motion \( T = \frac{2 \times v₀y}{g} \) - Here, g is the acceleration due to gravity (approximately \( 9.81 \, m/s² \)). 3. **Calculate Horizontal Range (R):** - \( R = v₀x \times T \) **Diagrams or Calculations:** (As the original image is text-based, create diagrams showing the projectile’s trajectory, the breakdown of the initial velocity into components, and the calculation steps.) Using these steps, you can determine the horizontal distance necessary for placing the portal. This application demonstrates fundamental principles of physics involving projectile motion.
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