The trapezoidal channel below must supply a discharge rate of 42 (m3/s). The Manning’s roughness of the channel is 0.021 (s/m1/3) and the channel slope is 0.0021 . The trapezoidal channel below must supply a discharge rate of 2 x SN (m/s). The Manning'sroughness of the channel is SN/1000 (s/m/3) and the channel slope is SN/10000.Div2HB = 6.5 mUse MS Excel spreadsheet to set up the problem, and solve for the normal depth D to anaccuracy of 4 decimal places. Show at least 5 iterations in your table.

Answered: Image /qna-images/answer/3843e92c-fcf6-4ff0-9012-5559d627c6cf.jpg

Answered: The trapezoidal channel below must…

The trapezoidal channel below must supply a discharge rate of 42 (m3/s). The Manning’s roughness of the channel is 0.021 (s/m1/3) and the channel slope is 0.0021 .

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 6. Find the normal depth for a discharge of 125 cfs in a trapezoidal channel with a bottom width of…

A: Given data Bottom widht (B) = 3 ft Side slope = (1:m) = (1 : 2 ) Bed slope (So) = 1% = 0.01…

Q: QUESTION 3 The two alternative dpeths in a 4.0 m wide rectangular channel are 3.86 m and 1.0 m,…

Q: A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel…

A: The given grass lined trapezoidal channel has a width is, 40 ft The given side slope is, below…

Q: Q2. A trapezoidal channel has a bed width of 3.0 m and side slope of 1 horizontal: 1 vertical. It…

Q: Design a trapezoidal channel to carry a discharge of 1000 cfs. The channel laid on a slope of 0.0015…

A: to find - design the trapezoidal channel

Q: The flow rate in a wide rectangular open channel is 2.0 m³/s per metre width. The channel bed slope…

A: Using Manning's equation

Q: A trapezoidal channel, bottom width 6 m and side slopes 1/1, flows 1.2 m deep on a slope of 0.0009.…

Q: The trapezoidal channel carrying a discharge of 100 m3 /sec. The bed of the channel descends at the…

A: Discharge in trapezoidal channel, Channel bed slope, NOTE Manning's constant,

Q: Water flows in a trapezoidal channel in which the bottom width is 6 m and the side slopes are 2:1…

A: The bottom width = 6 mSide slopes = 2 : 1 (H : V)n = 0.045Longitudinal slope of channel = 1.5%Flow…

Q: A rectangular channel has a width of 4.0 m and a bed slope of 0.006. The Manning's roughness of this…

Q: A discharge of 5.2 m³/s occurs in a rectangular channel of 2 m width having a bed slope of 1:625.…

A: Given: The discharge is 5.2 m3/sec. The width of the rectangular channel is 2 m. The bed slope is…

Q: The discharge in a rectangular channel of width 6 m with Manning's n = 0.012 m-1/3 s is 24 m³ s-¹.…

Q: A rectangular open channel of width 4.5m is carrying a discharge of 100 m³/s. The critical

Q: Is the flow subcritical or supercritical in a 4-m wide rectangular channel for a discharge of 9…

A: Objective: To determine if the given flow is subcritical or supercritical. Given: Width of the…

Q: 6-25. A rectangular channel 20 ft wide has a roughness coefficient n = 0.015. a. Determine the…

A: Given: Rectangular channel: width, b = 20 ft n = 0.015 To find: a) Normal slope at a normal depth of…

Q: At the outfall from a lake into a steep channel, the channel is of trapezoidal section with a base…

A: Given, b = 6 m m = 2

Q: find the normal depth for a discharge of 6.371m^3/s in a trapezoidal channel with a bottom width of…

A: GIVEN- Discharge Q=6.371 m3/sBottom width B=1.524 m Mannings constant n=0.012Side Slopes…

Q: The flow rate in a wide rectangular open channel is 2.0 m³/s per metre width. The channel bed slope…

Q: 7. A rectangular channel, 20 feet wide, carries a discharge of 200 cfs. Compute the critical depth…

Q: Example: A trapezoidal channel is 12.0 m wide and has a side slope of 1.5 horizontal: 1 vertical.…

A: The given data is shown below: Width=12mSide slope=1.5H:1VBed slope=0.0004n=0.015Depth of flow=3.5m

Q: 2.3 Find the normal depth for a discharge of 6.371 m³/s in a trapezoidal channel with a bottom width…

A: Given trapezoidal channel with side slope of 1H to 1V,Discharge, Q= 6.371 m3/sBottom width, B= 1.524…

Q: A surface drainage trapezoidal channel has to be designed for a drainage area of 500 ha. The…

A: Hello dear Please find the attached solution below, thanks

Q: A rectangular channel with a bottom width of 4.0m and a bottom slope of 0.0008 has a discharge of…

A: Given data, Q = 1.5 m^3/s B = 4 m n = 0.016 So = 0.0008 y = 0.3 m To find the

Q: Find the normal depth for a discharge of 350cfs in a rectangular channel with a bottom widith of 20…

Q: A rectangular channel with bottom width of 4.0 m and a bottom slope of 0.0008 has a discharge of…

Q: 0.0025

A: Area of the channel :A=120.25×2×0.25×tan60=0.108253m2Perimeter :P=0.25cos60=0.5m

Q: 5) A trapezoidal channel lined with stone (n=0.024) has a bottom width of 2.44 m, side slopes of 2.5…

Q: Q2. Design a trapezoidal channel having side slopes with z, a discharge of Q m³/s, with a velocity…

A: Given data, Q = 7 m3/s n = 0.017 v = 1.7 m/s z = 1.7 = 1/5.9 m = 5.9 B = Width y = Depth Therefore…

Q: Example: A concrete-lined trapezoidal channel (n = 0.015) is to have a side slope of 1.0 horizontal:…

A: Given:- The value of manning's coefficient (n) = 0.015 The side slope of the trapezoidal channel = 1…

Q: Determine the critical depth in a trapezoidal channel for a discharge of 150 m3/sec. The width of…

A: Considering side slope angle as 45 degrees

Q: A trapezoidal channel is to be designed to convey a discharge of 50 m³/sec at a velocity of 2 m/sec.…

A: GivenTrapezoidal channel-Discharge Q=50 m3/sVelocity V=2 m/sbed width to depth ratio-By=0.8side…

Q: Question 4 The flow rate in a wide rectangular channel is 5.0m³/sec/ m. The channel bed slope is…

A: Flow rate q = 5 m3/s/m, Bed slop of the channel S=0.0035, Manning's coefficient n=0.016,

Q: Determine the normal depth in a triangular channel with bed slope of 0.0005, n = 0.013 and central…

A: Triangular Channel Bed slope (S) = 0.0005 Manning coefficient (n) = 0.013 Central angle = 90°…

Q: Uniform flow occasionally occurs in a 5-m-diameter circular concrete conduit but the depth of flow…

A: Given data- diameter D= 5mn=0.013slope S=0.0005

Q: 3 The flow rate in a wide rectangular channel is 5.0m³/sec/ m. The channel bed slope is 0.0035. The…

A: Given data- A wide rectangular channel- Discharge per unit width- q=5 m3/s/m, Bed slope S=0.0035,…

Q: Is the flow subcritical or supercritical in a 4-m wide rectangular channel for a discharge of 9…

A: Given : width = 4m Discharge 9 m3/s bottom slope = 0.005 n = 0.014 To Find : if the flow is…

Q: A trapezoidal channel (n = 0.022, m=2) with a bottom width of 5m carries a discharge of 45 m³/s at a…

Concept explainers

Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.

Question

100%

The trapezoidal channel below must supply a discharge rate of 42 (m³/s). The Manning’s roughness of the channel is 0.021 (s/m^1/3) and the channel slope is 0.0021 .

The trapezoidal channel below must supply a discharge rate of 2 x SN (m/s). The Manning's
roughness of the channel is SN/1000 (s/m/3) and the channel slope is SN/10000.
D
iv
2H
B = 6.5 m
Use MS Excel spreadsheet to set up the problem, and solve for the normal depth D to an
accuracy of 4 decimal places. Show at least 5 iterations in your table.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

B-A trapezoidal channel with (b=3M, 2= 2M, S=0,0016 Manning coefficient n=0,025) carries discharge of (12 m³/sec). Find the normal depth and velocity?
4. A trapezoidal channel with 3 meters bottom width, side slope 2H:1V, channel gradient of 0.002, and n = 0.025, carries a discharge of 200 m3 /min. Compute the normal depth and velocity.
QUESTION A trapezoidal channel with 3 meters bottom width, side slope 2H: 1V, channel gradient of 0.002, and n = 0.025, carries a discharge of 200 m3/min. Compute the normal depth and velocity.
5. A tar coated (n = 0.014) triangular channel has 45ᵒ sides and slope of 0.0004. Compute the normal depth for a discharge of 140 ft3/s.
Q1. A compound channel section shown below carries flow on a longitudinal slope of 0.001. Determine discharge of flow if Manning coefficient is 0.022. 2 1.2 m 3 0.9 m 1.5 m 1.6 m
An open channel triangular section has a base of 3m. The side slope of the triangle is 450 from the horizontal on both sides. If S = 2.5/1000 and n = 0.012, determine the discharge in the open channel. A) No Answer among the choices B) 5.34 m3/s 9.75 m3/s D) 7.60 m3/s E) 3.23 m3/s
A trapezoidal channel (slope = 0.006, n = 0.014) has a bed width of 4 m and is with a side slope of 1:2 (V: H). The flow rate is 100 m³s-1. At a particular point canal confluences with a stream of 3.5 m depth. The invert elevations of the stream and the canal are same. Determine whether the flow in the channel is subcritical or supercritical flow. What is the type of control and stream represents the channel?
2. A 1.0 diameter channel must carry a discharge of 0.40 m³/s at a velocity of 0.8 m/s. n = 0.013 A) Compute the depth of water in the channel B) Compute the slope of the circular channel C) Determine the length of the channel if it drops 2 m at the end
: The width of a horizontal, rectangular channel is reduced from 3.5 to 2.5 m and the floor is raised by 0.25m in elevation at a given section. At the upper stream section the depth of flow is Im and the KE correction factor is 1.15. If the drop in water level at the contraction is 0.20m. Calculate loss is i) Discharge if energy • zero. ") Discharge if energy loss is 10th of the upper stream velocity head. KE correction factor for contracted section is unity. 2m y₁ 0.2m y: 2 0.25 m. 3.5 2.5m
The flow depth in a long trapezoidal channel (bottom width = 8 m, side slopes 1:1) for a flow of 28 m3/s is 3 m. The channel bottom slope is 0.0001. Determine the flow depth if the rate of discharge is doubled. Ans close to - 6.577m Need explanation how. No need to draw any diagram.
A 5 m wide rectangular channel carries a discharge of 16 m3/s. Manning's roughness coefficient for the channel is 0.012. The slope of channel bottom is 0.006. The depth of flow in channel required is decimal places) to carry the given discharge. Considering it is a wide channel. (in m, round off to two
5.1.3 Determine the uniform flow depth in a rectangular channel 2.5 ;m wide with a discharge of 3 m³/s. The slope is 0.004 and Manning's roughness factor is 0.015.