The total dead load is 6.5 kPa and the total live load is 3.8 kPa. Use the load combination: 1.2DL + 1.6LL. Ignore beam and wall weights. Answers must be in 3 decimal places. Absolute numerical inputs only. B-2 8-3 3.5m B-4 $1 $3 3.5m 8-6 B-G B-7 3m 8m 4m Determine the equivalent uniform load in kN/m for beam B-9 considering the combined dead and live load. 21-8 Il- al-8 b-9

Q: 32 The simple beam is loaded with service loads in adition to its selfweight. Check if the…

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Q: simply supported wood beam of length L = 10 ft carries a concentrated load P at midspan, as shown.…

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Q: A column in the upper story of a building is subjected to a compressive load from the following…

A: D = 308 kNL = 170 kNLr = 187 kNW = 197 kN To determine:a) factored loadb) Required design strength…

Q: Determine the allowable design axial load on a size 350mm x 350mm square column. The column has an…

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Q: The floor of one-story office building in the figure is made of 4-in.-thick normal weight concrete.…

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Q: Axially Loaded Determine the allowable design axial load on a size 350 mm x 350 mm square column.…

A: Given data - Size = 350×350 mm L = 3.5 m E = 33.56 GPa Fc = 11.70 MPa Find out - The allowable…

Q: Engineering Mechanics

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Q: Two plates are joined by four rivets of 20-mm diameter, as shown in the figure. Determine the…

A: Diamter = 20mmLimiting stressa in shear =80mpa = SsyFsb in tensile =100 mpa =SytFsc in bearing = 140…

Q: A 97-kN axial load P is applied to the W150 x 8 rolled steel column BC that is free at its top C and…

A: P = 97 kN e = 6 mm  σa = 80 MPa E = 200 GPa or 200,000 MPa

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.