Engineering Mechanics
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
Engineering
Based on the problem and solution given (see the attached solution) ,
determine the shear stress in the grain of the timber column shown in the figure. (See the attached image)
![Reactions:
ΣΜΑ ΤΟ
(10 x 6.5) (65) + (10x 5.5) (55³) + (1 2 × 3 × 15) (1.5 + 3×3) - R₂ X 6.5 = 0
x
Σ Fy = 0
211.25 +
Maximum
column
151.25 +
RA + RB
reaction
strength
80
=
N
mm²
78.75
R₂ = 67.885 KN
10x 6-5
RA
=
maximum
Reaction
10 x 5.5
74.615
6.5 RB = 0
74.615 KN
KN
area of column
74.615 X10³ N
Area
1/2/2x3x15
use
=0
Area = 932.6875 mm ²
31mm
x 31mm
(Area
=961 mm²)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F056d53dc-3f4d-4ce6-b212-dcc4942aa42d%2F761319bd-a003-41e7-aadb-0d6c0acbd73d%2Fn1ln13j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Reactions:
ΣΜΑ ΤΟ
(10 x 6.5) (65) + (10x 5.5) (55³) + (1 2 × 3 × 15) (1.5 + 3×3) - R₂ X 6.5 = 0
x
Σ Fy = 0
211.25 +
Maximum
column
151.25 +
RA + RB
reaction
strength
80
=
N
mm²
78.75
R₂ = 67.885 KN
10x 6-5
RA
=
maximum
Reaction
10 x 5.5
74.615
6.5 RB = 0
74.615 KN
KN
area of column
74.615 X10³ N
Area
1/2/2x3x15
use
=0
Area = 932.6875 mm ²
31mm
x 31mm
(Area
=961 mm²)
![3.00
F
a
40°
T](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F056d53dc-3f4d-4ce6-b212-dcc4942aa42d%2F761319bd-a003-41e7-aadb-0d6c0acbd73d%2F8nyf0qf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.00
F
a
40°
T
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