The titration of Na2CO3 (H₂CO3 has a pka1 = 6.37 and pka2 = 10.32) against HCl(aq) is depicted below: pH A B V₁ V₂ mL HC1 E F a) Identify the major species in solution at points A - F. b) For the titration of 25.00 mL of 0.100 M Na2CO3 against a 0.100 M HCl solution: i) calculate V₁ and V₂ ii) calculate the pH at points A - E. Note: points B and D are halfway points to equivalence.

The titration of Na2CO3 (H₂CO3 has a pka1 = 6.37 and pka2 = 10.32) against HCl(aq) is depicted below: pH A B V₁ V₂ mL HC1 E F a) Identify the major species in solution at points A - F. b) For the titration of 25.00 mL of 0.100 M Na2CO3 against a 0.100 M HCl solution: i) calculate V₁ and V₂ ii) calculate the pH at points A - E. Note: points B and D are halfway points to equivalence.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

The titration of Na₂CO3 (H₂CO3 has a pka1 = 6.37 and pka2 = 10.32) against HCl(aq) is depicted below:
pH
B
V₁
V₂
mL HC1
E
F
a) Identify the major species in solution at points A - F.
b) For the titration of 25.00 mL of 0.100 M Na₂CO3 against a 0.100 M HCl solution:
i) calculate V₁ and V₂
ii) calculate the pH at points A - E. Note: points B and D are halfway points to equivalence.

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