The titanium content in an aircraft-grade alloy is an important determinant of strength. Asample of 20 test coupons reveals the following titanium content (in percent):8.32, 8.05, 8.93, 8.65, 8.25, 8.46, 8.52, 8.35, 8.36, 8.41, 8.42, 8.30, 8.71, 8.75, 8.60, 8.83, 8.50,8.38, 8.29, 8.46. The median titanium content should be 8.5%.Use the sign test with a = 0.05 to investigate this hypothesis. Match the answers.Parameter of Interest:a.r- = 12v Null and Alternative Hypothesis:b.r = min (R+,R-)c.r sr.Test Statistic:d.Reject the null hypothesis if.e. Η0 μ=8.5H;u#8.5Conclusion:f. Mean of the Titanium contentg. Median Titanium contenth. Η: μ 8.5H:ñ + 8.5i. Fail to reject the null hypothesis. There is not enough evidence toconclude that the median of the titanium content differs from 8.5%.j. Reject the null hypothesis. The median of the titanium content differsfrom 8.5%.

Given data are, xi : 8.32, 8.05, 8.93, 8.65, 8.25, 8.46, 8.52, 8.35, 8.36, 8.41, 8.42, 8.30, 8.71,…

Answered: The titanium content in an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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C-4) The concentration of active ingredient in a liquid laundry detergent is thought to be affected by the type of catalyst used in the process. Ten observations on concentration are taken with each catalyst, and the data follow: Catalyst 1: 57.9, 66.2. 65.4, 65.4, 65.2. 62.6, 67.6, 63.7, 67.2. 71.0 Catalyst 2: 66.4. 71.7. 70.3. 69.3, 64.8, 69.6, 68.6, 69.4, 65.3, 68.8. Find a 95% confidence interval on the ratio of active concentrations for the two catalysts, and explain it.
In an attempt to develop a model of wine quality as judged by wine experts, data on alcohol content and wine quality was collected from variants of a particular wine. From a sample of 12 wines, a model was created using the percentages of alcohol to predict wine quality. For those data, SSR=19,812 and SST=30,298. Use this information to complete parts (a) through (c) below. a. Determine the coefficient of determination, r2, and interpret its meaning. r2=enter your response here (Round to three decimal places as needed.) Interpret the meaning of r2. It means that enter your response here% of the variation in ▼ alcohol content wine quality can be explained by the variation in ▼ alcohol content. wine quality. (Round to one decimal place as needed.) b. Determine the standard error of the estimate. SYX=enter your response here (Round to four decimal places as needed.) c. How useful do you think this regression model is for predicting wine…
From the data given below, calculate the gross and net reproduction rates : Age Group Female Population (in thousands) Female Live-births Survival Factor 15-19 1,399 15,133 0.9694 20-24 1,422 94,155 0.9663 25-29 1,521 102,676 0.9632 30-34 1,756 72,490 0.9584 35-39 1,451 31,402 0.9519 40-44 1,689 10,640 0.9424 45-49 1,667 700 0.9279
The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite). 1: 20.6 28.1 27.8 27.0 27.9 25.2 25.3 27.1 20.5 31.2 2: 26.5 24.0 26.2 20.2 23.6 34.0 17.1 26.8 23.7 24.8 3: 30.2 34.0 27.5 29.4 28.3 26.2 29.9 29.5 30.0 35.8 4: 36.6 44.2 34.1 30.3 32.0 33.1 34.1 32.9 36.3 25.2 Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4Ha: at least two ?i's are equalH0: ?1 = ?2 = ?3 = ?4Ha: all four ?i's are unequal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4Ha: all four ?i's are equalH0: ?1 = ?2 = ?3 = ?4Ha: at least two ?i's are unequal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Source df Sum ofSquares MeanSquares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.)
The following data was reported on total Fe for four types of iron formation (1 carbonate, 2 silicate, 3 magnetite, 4 hematite). 1: 21.0 28.1 27.8 27.0 27,8 25.2 25.3 27.1 20.5 31.5 2: 26.2 24.0 26.2 20.2 23.6 34.0 17.1 26.8 23.7 25.0 3: 29.6 34.0 27.5 29.4 26.4 26.2 29.9 29.5 30.0 35.5 4: 37.1 44,2 34.1 30.3 31.8 33.134.1 32.9 36,3 25.3 A USE SALT Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. H at least two 's are equal Ho Hi= Ha = H4 H at least two 's are unequal O Ho = = 4 H al four s are unequal H all four 's are equal
Six samples of each of four types of cereal grain grown in a certain region were analyzed to determine thiamin content, resulting in the following data (µg/g). Wheat 5.2 4.4 6.1 6.2 6.6 5.8 Barley 6.5 7.9 6.0 7.6 6.0 5.7 Maize 5.8 4.6 6.4 4.9 6.0 5.2 Oats 8.4 6.2 7.8 7.1 5.4 7.2 USE SALT Does this data suggest that at least two of the grains differ with respect to true average thiamin content? Use a level α = 0.05 test. State the appropriate hypotheses. | H₂: M₁ = H₂ = H3 = H4 H₂: all four μ's are unequal • Ho: M₁ = H₂ = H3 = H4 H₂: at least two μ's are unequal ⒸH₂² H₁ H₂ H3 H4 # H: all four μ's are equal O Ho: M₁ #M₂ #H3 H4 H₂: at least two μ's are equal Compute the test statistic value. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 State the conclusion in the problem context. O Reject Ho. There is not significant evidence…
llustration 21.14. Calculate the coefficient of contingency from the following data relating social status and intelligence: Social Status Dull Brilliant Average 35 Lower Middle Middle 22 23 38 70 32 Upper Middle 60 20 20
The following is data about the hemoglobin concentrations of volunteers collected at sea level and at an altitude of 11000 feet. sea level concentrations = [14.70 , 15.22, 15.28, 16.58, 15.10 , 15.66, 15.91, 14.41, 14.73, 15.09, 15.62, 14.92]11000 feet concentrations = [14.81, 15.68, 15.57, 16.59, 15.21, 15.69, 16.16, 14.68, 15.09, 15.30 , 16.15, 14.76] There are two alternative scenarios about the way the data were obtained. In scenario 1, there are 12 volunteers who lived for a month at sea level, at which time blood was drawn and the data in "sea level concentrations" dataset were obtained. Subsequently, all 12 volunteers were moved to 11000 ft and after a month the data in the "11000 feet concentrations" dataset obtained. There is a one to one correspondence between the numbers in the two datasets, that is the first numbers correspond to volunteer1, the second numbers to volunteer2 etc. In scenario 2, the "sea level concentrations" dataset is a random sample obtained from 12…
2 In building electronic circuitry, the breakdown voltage of diodes is an important quality char- Acteristic. The breakdown voltage of 12 diodes were recorded as follows (in volta): 9.099 9.174 9.327 9.377 8.471 9.575 9.514 8.928 8.800 8.920 9.913 8.306 Solution A quality engineer claimed that the variability of the breakdown voltage is not less than 0.55. Can the data support the engineer's claimed at a 0.057 ii. If level of significance is reduced to 0.02, will you change the conclusions you have made in (i)? Justified your answer.
There is a relationship between political affiliation (on a scale of 1 to 10, where 1 = very liberal and 10 = very conservative) and U.S. geographic regions, such that people living in the Northeast are more likely to consider themselves liberal than people living in the South. what is my unit of analysis?
Let n=23 and consider the following information, Model One: Y = Bo + B1X, + B2X2 + B3 X3 + B4X, +e and R 90.62% Model Two: Y Bo + B1X1 + B2X2 + B4X4 + e and R2 = 82.55%, Model Three: Y = Bo+ B1X1 + B2X2 + B3X3 te and R2 Model Four: Y = Bo + B,X1 + B,X, +e and R? 86.85%, 81.19%. %3| Consider testing that Ho : B1 = B2 = B3 = 0. The value of the computed test statistic is Select one: O a. 74.45 O b. 41.83 Oc. 29.96 O d. 43.46

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