The time taken for a computer to boot up, X, follows a mound-shaped (i.e. bell-shaped) distributionwith a mean of 30 seconds and a standard deviation of 5 seconds.What is the standardized score for a boot up time of...a. x = 30 seconds?b. x = 20 seconds?c. x = 35 seconds?1Z-Score =Z-Score =Z-Score =h

The standardized score, also known as the z-score, is a measure of how many standard deviations an…

Answered: The time taken for a computer to boot…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume the mean useful life of a particular light bulb is 2,000 hours, which is normally distributed with a standard deviation of 300 hours. What is the range of the useful life of light bulbs within two standard deviations of the mean? A. Between 1,400 and 2,600 hours B. Longer than 2,300 hours C. Between 1,700 and 2,300 hours D. Longer than 1,700 hours
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Q.Discuss coefficient of mean deviation.
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Internet Service Providers The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50 and the standard deviation is $20. The distribution is not Normal: many households pay a low rate as part of a bundle with phone or television service, but some pay much more for Internet only or for faster connections. A sample survey asks an SRS of 50 households with Internet access how much they pay. Let x be the mean amount paid. 1. Explain why you can't determine the probability that the amount a randomly selected household pays for access to the Internet exceeds $55. 2. What are the mean and standard deviation of the sampling distribution of x ? 3. What is the shape of the sampling distribution of x ? Justify your answer. 4. Find the probability that the average fee paid by the sample of households exceeds $55.
d. Determine the sample standard deviation. Round your answer to 2 decimal places. e. Determine the coefficient of variation.
Recently, a random sample of 25-34 year olds was asked, "How much do you currently have in savings, not including retirement savings?" The data in the table represent the responses to the survey. Approximate the mean and standard deviation amount of savings. E Click the icon to view the frequency distribution for the amount of savings. The sample mean amount of savings is $ Frequency distribution of amount of savings (Round to the nearest dollar as needed.) The sample standard deviation is S (Round to the nearest dollar as needed.) Frequency Savings $0 $199 $200-$399 $400 $599 $600 $799 $800 $999 $1000-$1199 $1200 $1399 342 86 45 21 10 7 1 Print Done
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.727 and standard deviation o = S1.041. E Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates The population mean is $ Tax Rate 0.00-0.49 0.50-0.99 1.00-1,49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 Frequency D (Round to three decimal places as needed.) 5 15 The population standard deviation is S (Round to three decimal places as needed.) Compare these results to the values found using the actual data. O A. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. O B. The grouped values are both slightly larger. O C. The grouped values are both slightly smaller. O D. The grouped mean is slightly smaller, while the grouped standard…
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