The three-span beam shown in Fig. P.20.7 has hinges at C and E in its central span. Construct influence lines for the reaction at B and for the shear force and bending moment at the sections K and D. Ans. Influence line ordinates Rg; A=0, B=1, C=1.25, E=F=G=0. Sk: A %3D 0, К%3D+0.5, В — 0, С%3D + 0.25, Е%3D0. Sp; A=B=0, D=-1.0, C=-1.0, E=F=G=0. Мк: А — В— 0, К-1.0, С—-0.5, Е—F3G-0. Mp; A=B=D=0, C=-0.5, E=F=G=0.

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The three-span beam shown in Fig. P.20.7 has hinges at C and E in its central span.
Construct influence lines for the reaction at B and for the shear force and bending moment
at the sections K and D.
Ans. Influence line ordinates
Rg; A=0, B=1, C=1.25, E=F=G=0.
SK; A=0, K=±0.5, B=0, C= + 0.25, E=0.
Sp; A=B=0, D=-1.0, C=-1.0, E=F=G=0.
Mg; A=B=0, K=1.0, C=-0.5, E=F=G=0.
Mp; A=B=D=0, C=-0.5, E=F=G=0.
Transcribed Image Text:The three-span beam shown in Fig. P.20.7 has hinges at C and E in its central span. Construct influence lines for the reaction at B and for the shear force and bending moment at the sections K and D. Ans. Influence line ordinates Rg; A=0, B=1, C=1.25, E=F=G=0. SK; A=0, K=±0.5, B=0, C= + 0.25, E=0. Sp; A=B=0, D=-1.0, C=-1.0, E=F=G=0. Mg; A=B=0, K=1.0, C=-0.5, E=F=G=0. Mp; A=B=D=0, C=-0.5, E=F=G=0.
K
D C
E
F
0.5 m 0.5 m
2 m
2 m
1 m
1 m
4 m
Transcribed Image Text:K D C E F 0.5 m 0.5 m 2 m 2 m 1 m 1 m 4 m
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