power factor isThe three phase power and line-line ratings of the below electric power system is given below:VgVmMG: 50 MVA20 KVX= 4%T: 50 MVA20/40 KVX= 4%M: 43.2 MVA36 KVX= 4%By choosing 100 MVA and 20 KV on the generator side as base values, the new per unit impedance of the generator isand the new perunit impedance of the motor is7.5%None of thesea load absorbs 50 MVA at 0.8 pf leading at line to line voltage of 18 KV 10.238%11.43%find the perunit impedance of this load on a base of 100MVA and 208.333%Select one:O a. 5.183-j3.888 puOb. 5.183 +j 3.888 puO c. 1.295 -j0.972 pu1:49 AMEN4/14/20 power factor isThe three phase power and line-line ratings of the below electric power system is given below:T.VmMG: 50 MVA20 KVX= 4%T: 50 MVA20/40 KVX= 4%M: 43.2 MVA36 KVX= 4%By choosing 100 MVA and 20 KV on the generator side as base values, the new per unit impedance of the generator isand the new perunit impedance of the motor is16 %None of these8%VA at 0.8 pf leading at line to line voltage of 18 KV.4%bedance of this load on a base of 100MVA and 20 KV.Select one:O a. 5.183-j3.888 puOb. 5.183 + j 3.888 puOc.1.295-10.972 puEN O1:49

In this question we will find reactance of generator and motor on new base ..

The three phase power and line-line ratings of the below electric power system is given below: Vg Vm M G: 50 MVA 20 KV X= 4% T: 50 MVA 20/40 KV X= 4% M: 43.2 MVA 36 KV X= 4% By choosing 100 MVA and 20 KV on the generator side as base values, the new per unit impedance of the generator is and the new perunit impedance of the motor is 7.5% None of these a load absorbs 50 MVA at 0.8 pf leading at line to line voltage of 18 KV 10.238% 11.43% find the perunit impedance of this load on a base of 100MVA and 20 8.333% Select one: O a. 5.183 -j 3.888 pu Ob. 5.183 +j 3.888 pu OC. 1.295-10.972 pu 1:49 EN 4714

The three phase power and line-line ratings of the below electric power system is given below: Vg Vm M G: 50 MVA 20 KV X= 4% T: 50 MVA 20/40 KV X= 4% M: 43.2 MVA 36 KV X= 4% By choosing 100 MVA and 20 KV on the generator side as base values, the new per unit impedance of the generator is and the new perunit impedance of the motor is 7.5% None of these a load absorbs 50 MVA at 0.8 pf leading at line to line voltage of 18 KV 10.238% 11.43% find the perunit impedance of this load on a base of 100MVA and 20 8.333% Select one: O a. 5.183 -j 3.888 pu Ob. 5.183 +j 3.888 pu OC. 1.295-10.972 pu 1:49 EN 4714

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Please solve d, e, f ONLY.
part F please
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