# The three lines of Abc.txt contain a b, c, d infile = open("Abc.txt", 'r') alpha = [line.rstrip() for line in infile] infile.close() word = ("").join(alpha) print(word)
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- For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() {const int SIZE_LIST = 4;vector<int> keysList(SIZE_LIST);vector<int> itemsList(SIZE_LIST);unsigned int i; for (i = 0; i < keysList.size(); ++i) {cin >> keysList.at(i);} for (i = 0; i < itemsList.size(); ++i) {cin >> itemsList.at(i);} /* Your solution goes here */ cout << endl; return 0;} Please help me with this problem using c++.Q2 Answer Q2(a)-Q(d) based on the information given in Figure Q2. to record daily information of at Liney Restaurant. The program creates a linked list in /"This program is meant the menu available which each node contains data such as menu name, price per unit, preparation time, quantity ordered and a pointer. The declaration of the structures MenuData and MenuNode are given in the program.*/ tinclude tinclude tinclude #define SIZE 20 struct Menubata char menuName (20]; double price PerUnit; double prepzime; int quantityordered, typedef struct Menubata MenuData; struct MenuNode MenuData data; struct MenuNode *next; typedef struct Menutode MenuNode, void showPrepTime (MenuNode *fftr): int main () MenuNode *front = NULL, *newNodePtr; MenuData input Data, for (int i=l; i<=SIZE, i++) printf ("\nEnter menu name: "): gets (inputData.menuName): printf ("\nEnter price per unit: "); scanf ("$lf", 5inputData.pricePerUnit); printf("\nEnter preparation time (hours): "): scanf ("lf", &input…Q.Create an interesting educational information chat box that asks the user to give an input question and then answers the question given by user with a suitable answer. You can make use of list for different questions and answers.Save two to three answers for a single question and then for random selection of elements from those answers use random choice(list) method from random module that returns a random element. Also for a user question that doesn't matches with the questions present in the chat box it should display statement like "oops i can't answer that" "sorry i am not intelligent enough" "could u please ask something else" using random method so that every time one of these statements appear **coding language python ***try using basic programming techniques in python without using arrays and pointers * * * copy paste the program itself and also the screenshot of program and output * * * use any type of data for questions such as name details of cities species etc depends on…
- filter=df['age']=='30' print(df[filter]) print(df.loc[filter,:]) Select an answer: They will both print the exact same results. They will both fail with a syntax error. The first call will only print the rows. The second call will only print true or false messages.Q.Create an interesting educational information chat box that asks the user to give an input question and then answers the question given by user with a suitable answer. It should match the question of user with a suitable answer avaliable . You can make use of list for different questions and answers. (if possible) Save two to three answers for a single question and then for random selection of elements from those answers use random choice(list) method from random module that returns a random element. Also for a user question that doesn't matches with the questions present in the chat box it should display statement like "oops i can't answer that" "sorry i am not intelligent enough" "could u please ask something else" using random method so that every time one of these statements appear **coding language python ***try using basic programming techniques in python without using arrays and pointers * * * copy paste the program itself and also the screenshot of program and output…When you print an instance of the class Food in Question 1, you get something like this: Building up your answer coder in Question 1, write a str 0 method for the class Food so that printing an instance of the class results in a string that is a combination of the value of the attributes taste and name, separated by a blank: DO NOT call the function. For example:
- Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…Using Java programming language create a linked list named Cars with four elements: "SUV cars", "Pickup cars", "Sport cars", and "Sedan cars". Apply the following activities on the code you’ve created and provide screen shot of each result: Add a new element “Classic car” at the beginning of the linked list using iterator. Add a new element “Economic cars" after the element "Sedan Cars" using iterator. Print the LinkedList backward from the last element to the first element using hasPrevious()Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10), print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. 1 #include HNm in 10 m DO G 2 3 int main(void) { 4 5 6 const int NUM_VALS = 4; int courseGrades [NUM_VALS]; int i; 7 8 for (i = 0; i < NUM_VALS; ++i) { scanf("%d", &(courseGrades[i])); 9 } 10 11 12 13 14 15 } /*Your solution…
- Q.Create an interesting educational information chat box that asks the user to give an input question and then answers the question given by user with a suitable answer. It should match the question of user with the answer avaliable. Make use of list for different questions and answers. (if possible) Save two to three answers for a single question and then for random selection of elements from those answers use random choice(list) method from random module that returns a random element. Also for a user question that doesn't matches with the questions present in the chat box it should display statement like "oops i can't answer that" "sorry i am not intelligent enough" "could u please ask something else" using random method so that every time one of these statements appear **coding language python ***try using basic programming techniques in python without using arrays and pointers * * * copy paste the program itself and also the screenshot of program and output * * * use any…dict_graph = {} # Read the data.txt file with open('data.txt', 'r') as f: for l in f: city_a, city_b, p_cost = l.split() if city_a not in dict_graph: dict_graph[city_a] = {} dict_graph[city_a][city_b] = int(p_cost) if city_b not in dict_graph: dict_graph[city_b] = {} dict_graph[city_b][city_a] = int(p_cost) # Breadth First Search Method def BreadthFirstSearch(graph, src, dst): q = [(src, [src], 0)] visited = {src} while q: (node, path, cost) = q.pop(0) for temp in graph[node].keys(): if temp == dst: return path + [temp], cost + graph[node][temp] else: if temp not in visited: visited.add(temp) q.append((temp, path + [temp], cost + graph[node][temp])) # Depth First Search Method def DepthFirstSearch(graph, src, dst): stack = [(src, [src], 0)] visited = {src} while stack:…Evaluate the following expressions a. foldFromLeft(minus, 6, map(RemoveTwo, [3, 4, 8])) b. foldFromRight(minus, 6, map(RemoveTwo, [3, 4, 8]))
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