The three-electron wavefunction for the configuration 1s² 2s¹ is properly written with the following determinant: 1sa(1) 1sẞ(1) 2sa(1) 1 = 1sa(2) 1sẞ(2) 2sa(2) √3! 1sa(3) 1sẞ(3) 2sa(3) Write out the linear combination that this represents, and verify that the wavefunction is antisymmetric with respect to electron exchange. Next, verify that the 1s orbital can not hold a third electron - you can do this by changing the 2sa label in the determinant to 1sa, expanding the determinant, and evaluating the result.

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The three-electron wavefunction for the configuration 1s² 2s¹ is properly written with the
following determinant:
1sa(1) 1sẞ(1) 2sa(1)
1
=
1sa(2) 1sẞ(2) 2sa(2)
√3!
1sa(3) 1sẞ(3) 2sa(3)
Write out the linear combination that this represents, and verify that the wavefunction is
antisymmetric with respect to electron exchange. Next, verify that the 1s orbital can not hold a
third electron - you can do this by changing the 2sa label in the determinant to 1sa, expanding
the determinant, and evaluating the result.
Transcribed Image Text:The three-electron wavefunction for the configuration 1s² 2s¹ is properly written with the following determinant: 1sa(1) 1sẞ(1) 2sa(1) 1 = 1sa(2) 1sẞ(2) 2sa(2) √3! 1sa(3) 1sẞ(3) 2sa(3) Write out the linear combination that this represents, and verify that the wavefunction is antisymmetric with respect to electron exchange. Next, verify that the 1s orbital can not hold a third electron - you can do this by changing the 2sa label in the determinant to 1sa, expanding the determinant, and evaluating the result.
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