The three-electron wavefunction for the configuration 1s² 2s¹ is properly written with the following determinant: 1sa(1) 1sẞ(1) 2sa(1) 1 = 1sa(2) 1sẞ(2) 2sa(2) √3! 1sa(3) 1sẞ(3) 2sa(3) Write out the linear combination that this represents, and verify that the wavefunction is antisymmetric with respect to electron exchange. Next, verify that the 1s orbital can not hold a third electron - you can do this by changing the 2sa label in the determinant to 1sa, expanding the determinant, and evaluating the result.

The three-electron wavefunction for the configuration 1s² 2s¹ is properly written with the following determinant: 1sa(1) 1sẞ(1) 2sa(1) 1 = 1sa(2) 1sẞ(2) 2sa(2) √3! 1sa(3) 1sẞ(3) 2sa(3) Write out the linear combination that this represents, and verify that the wavefunction is antisymmetric with respect to electron exchange. Next, verify that the 1s orbital can not hold a third electron - you can do this by changing the 2sa label in the determinant to 1sa, expanding the determinant, and evaluating the result.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter7: Electronic Structure

Section: Chapter Questions

Problem 7.53QE

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