The testing times for a group of college students were normally distributed with a mean of = 38 minutesand a standard deviation of a = 2.9 minutes.The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equalto the standard deviation.Fill in the indicated boxes.μ.30 μ-20 μ-oμ+95% of testing times were betweenUse the Empirical Rule to complete the following statements:68% of testing times were between99.7% of testing times were between50% of testing times were belowH=38σ 2.9μ+20 μ+30minutes andminutesminutes andminutes.minutes.minutes.minutes.

Given data: Population mean= 38 minutes Population standard deviation = 2.9 minutes

Answered: The testing times for a group of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The lengths of nails produced in a factory are normally distributed with a mean of 3.343.34 centimeters and a standard deviation of 0.070.07 centimeters. Find the two lengths that separate the top 3%3% and the bottom 3%3%.
Assume that the heights of women are normally distributed with a mean of 62.4 inches and a standard deviation of 1.6 inches. Find Q3 the third quartile that separates the bottom 75% from the top 25%
Find the range, vanance, and standard deviation for the given sample data. Include appropriate units in the results. Listed below are the measured radiation absorption rates (in Wikg) corresponding to various cell phone models. If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use? 1.16 0.82 0.51 0.69 1.11 0.82 0.69 0.75 0.52 0.53 1.34
The concentration of blood hemoglobin in middle-aged adult females is normally distributed with a mean of 13.5 g/dL and a standard deviation of 0.86 g/dL. Determine the hemoglobin levels corresponding to the: 90th percentile Middle 85% of middle-aged adult female hemoglobin levels
The number of leaves on apple seedlings aged 2 months followed a normal distribution, the average was 12sheet with a standard deviation of 2. What is the % of plant seeds that have a. at least 10 sheetsb. between 10 to 12 sheetsc. more than 14 sheets.
A variable is normally distributed with mean 39 and standard deviation 13. Use the Cumulative Z-Score Table to answer the following questions. Write your answers in decimal form using 4 decimal places. a) Find the area under the normal curve to the left of the data value 62.4. b) Find the area under the normal curve to the left of the data value 66,3. c) Find the area under the normal curve to the right of the data. value 51.35. d) Find the area under the normal curve to the right of the date value 43.55. e) Find the area under the normal curve between the data values 43.55 and 66.3.
Acorns in the northern Atlantic regions of the U. S. have an average volume of 3.75 cubic centimeters, with a standard deviation of .85 centimeters. If we were to collect 1000 samples of 300 randomly-selected acorns, describe the sampling distribution for the sample mean of acorn volumes. Round to the nearest hundredth (two decimal places) if necessary. Shape: Center: Spread:
When members of a philanthropic organization send out a fundraising letter, they get a return from about 7% of the people on their mailing list. They simulated 1000 mailings for samples of size n with success rate p = 0.07. The sample statistics from each simulation are shown in the table. Complete parts (a) through (d) below. Click the icon to view histograms of the simulations. n 20 theoretical standard deviation n 20 50 100 200 a) According to the Normal model, what should the theoretical mean and standard deviations be for these sample sizes? Complete the following table. theoretical mean 50 100 200 (Round to four decimal places as needed.). mean 0.0699 0.0708 0.0705 0.0693 standard dev. 0.0567 0.0366 0.0256 0.0179
What is the z score for 20 if mean =18 and stadnard deviation =0.5

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