The test statistics that z=-2.53 is obtained when testing the claim that p<0.25 A. use a signifigance level of 0.05 find the criticial value(S) B. Should we reject the null hypothesis or fail to reject the null hypothesis
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The test statistics that z=-2.53 is obtained when testing the claim that p<0.25
A. use a signifigance level of 0.05 find the criticial value(S)
B. Should we reject the null hypothesis or fail to reject the null hypothesis
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- I need help with trying to rationalize the less portion of the question. Please help me understand whether to reject or fail the hypothesis because there is or isn't enough evidence to support or reject the claim. The claim:H0: ≤1250.48 Ha: >1250.48 Standardized Test Statistic: 1.52P-Value: 0.064 (Fail to reject or reject). At the 1% significance level, there (is or is not) enough evidence to (support or reject) the claim.The test statistic of z = 2.05 is obtained when testing the claim that p > 0.4. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of α = 0.10, should we reject H0 or should we fail to reject H0?I already answered the ones I understand I just need help with the two that are blank. Thanks! 
- The graph portrays the decision criterion for a one-mean z-test. The curve in the graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. Use the graph to solve the problem. A graphical display of the decision criterion follows. Reject Ho 0.025 -3 -2 -1 -1.96 Do not reject Ho O-1.96 ≤ z ≤ 1.96 Oz≤-1.96 O z ≥ 0.025 Ozz-1.96 0 Determine the nonrejection region. 1 2 3 ZYou wish to test the following claim (Ha) at a significance level of a = 0.001. H,:P = P2 Ha:pi > p You obtain 303 successes in a sample of size n = 488 from the first population. You obtain 159 successes in a sample of size ry = 266 from the second population. What is the test statistic for this sample? test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O There is not sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O The sample data support the claim that the first population…Please help! This is the part 'c' since it got cut off in the picture: (c)Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 75 . Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 75 . Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 75 . Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to…
- x 8.2.13-1 Question Help Suppose 204 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p>0.20 Hq:p=0.20 B. Ho: p=0.20 Hq:p>0.20 O C. Ho: p=0.20 Hq:p 0.20 O D. Ho:p=0.20 Hq:p<0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer. ? 2 parts remaining Clear All Check Answer FAGER henery 595 17 80 OCT 4. étv Aa 21 MacBook Air 吕0 DII DD F10 F11 F12 F3 F4 F5 F6 F7 F8 F9 F2 $ & * 3 4 5 6 7 8 9 dele { R Y U | P ....The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. LOADING... Click the icon to view the display from technology. Question content area bottom Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=4.00 Mbps H1: μ>4.00 Mbps B. H0: μ<4.00 Mbps H1: μ=4.00 Mbps C. H0: μ=4.00 Mbps H1: μ≠4.00 Mbps T-Test μ<4.00 t=−2.869485 p=0.003303 x=3.43 Sx=1.256322 n=40 Identify the test statistic.You wish to test the following claim (Ha) at a significance level of a = 0.01. H.:P1 = P2 Ha:P1 > P2 The 1st population's sample has 74 successes and a sample size = 371. The 2nd population's sample has 47 successes and a sample size = 396. What is the test statistic (z-score) for this sample? (Round to 3 decimal places.) test statistic = What is the p-value for this sample? (Round to 3 decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null O fail to reject the null accept the null As such, the final conclusion is that... O The sample data support the alternate hypothesis claim that p1 > p2. O There is not sufficient sample evidence to support the alternate hypothesis claim that p1 > p2.
- Please Let Me Know the answerLet's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times (or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, and 8. The true mean (p) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (HM) would equal , and the standard deviation of your sampling distribution of means (that is, the standard error or GM) would be The following chart shows the sampling distribution of the…represents the summary statistics for 44 blue catfish caught at this reservoir, and a 0.05 significance level to test the claim that the mean weight of the fish in the John H. Kerr Reservoir is greater than 40 pounds. n = 44; = 40.76 pounds; s = 5.12 pounds a) kdentify the null and alternative hypotheses? Ho: =V 40 H.:p>v40 b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? O left-tailed O right-tailed O two-tailed c) Identify the appropriate significance level. 0.05 d) Calculate your test statistic. (Round your final answer to two decimal places.) e) Calculate your p-value. (Round your final answer to four decimal places.) f) Do you reject the null hypothesis? O We reject the null hypothesis, since the p-value is less than the significance level. O We reject the null hypothesis, since the p-value is not less than the significance level. O We do not reject the null hypothesis, since the p-value is less than the significance level. O We do not reject the…