The test statistic was found to be x there will be (r – 1)(c – 1) degrees of freedom where r is the number of rows and c is the number of co from the observed frequencies. The given observed data are below. = 3.949. For a test of independence between two categorical varia Age Group Hours of Sleep 39 or younger 40 or older Total Fewer than 6 38 36 74 6 to 6.9 60 57 117 7 to 7.9 76 74 150 8 or more 66 93 159

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Step 5
The test statistic was found to be x
= 3.949. For a test of independence between two categorical variables,
there will be (r – 1)(c – 1) degrees of freedom where r is the number of rows and c is the number of columns
from the observed frequencies. The given observed data are below.
Age Group
Hours of Sleep
39 or younger
40 or older
Total
Fewer than 6
38
36
74
6 to 6.9
60
57
117
7 to 7.9
76
74
150
8 or more
66
93
159
Total
240
260
500
There arer =
rows for the hours of sleep and c =
columns for the age group.
Thus, there are (r – 1)(c – 1) =
degrees of freedom.
Recalling that this is an upper tail test, use technology to find the p-value for x = 3.949, rounding the result
to four decimal places.
p-value =
Submit
Skip (you cannot come back)
Transcribed Image Text:Step 5 The test statistic was found to be x = 3.949. For a test of independence between two categorical variables, there will be (r – 1)(c – 1) degrees of freedom where r is the number of rows and c is the number of columns from the observed frequencies. The given observed data are below. Age Group Hours of Sleep 39 or younger 40 or older Total Fewer than 6 38 36 74 6 to 6.9 60 57 117 7 to 7.9 76 74 150 8 or more 66 93 159 Total 240 260 500 There arer = rows for the hours of sleep and c = columns for the age group. Thus, there are (r – 1)(c – 1) = degrees of freedom. Recalling that this is an upper tail test, use technology to find the p-value for x = 3.949, rounding the result to four decimal places. p-value = Submit Skip (you cannot come back)
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