The test statistic for testing HO: mu = 100 against Ha: mu != 100 was t = 3.3, with p-value of 0.001.Which of these is the correct conclusion?O Since the p-value is very small, we conclud that mu != 100Since the p-vaue is very smal, we are unable to conlude that mu != 100O Since the p-value is very small, we must conclude the mu = 100In order to interpret the results, we must first know the sample size.Since the p-value is very small, we are unable to conclude that mu = 100.

Answered: Image /qna-images/answer/8616c07c-6156-4dd7-a050-e707fa04191c.jpg

Answered: The test statistic for testing HO: mu =…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The test statistic for testing HO: mu = 100 against Ha: mu != 100 wast 3.3, with p-value of 0.001. Which of these is the correct conclusion? Since the p-value is very small, we conclud that mu != 100 Since the p-vaue is very smal, we are unable to conlude that mu != 100 Since the p-value is very small, we must conclude the mu = 100 In order to interpret the results, we must first know the sample size. Since the p-value is very small, we are unable to conclude that mu = 100.
When using a Chi-square test, the expected frequency, E, has to be at least 5. State two possible approaches that can be implemented when the expected frequency, E, is less than 5.
Please solve these subparts of the attached image question manually and using R-studio code, not an excel output. Thanks so much! a) We want to test if there is a difference in the mean heart rates for the three groups. Give the null hypothesisof this test. b) Does the data suggest that there is a difference among the three groups? Use α = 0.05.c) If there seems to be a difference, complete a Bonferroni pairwise test to determine which or if all the meansare different from each other.
How would a person set up the hypotheses if they wanted to test the claim: the mean temperature of a October day in Oahu is different from 81 degrees? A: Ho µ = 81° vs HA H > 81° B: Ho H = 81° vs HA H 81° A
Please no written by hand solution and no img . Pairs of hypotheses about a claim (a statistic of the population, like its mean, μ) include the following: (A) H0: μ ³ k and Ha: μ < k, where k is some value (B) H0: μ = k and Ha: μ ≠ k, where k is some value (C) H0: μ > k and Ha: μ £ k, where k is some value (D) H0: μ £ k and Ha: μ > k, where k is some value (E) H0: μ < k and Ha: μ ³ k, where k is some value
4. For a sign test for paired data, it is given that np = 9, nq= 8. The method that we use for testing is. • Normal • Binomial • Chi square • t-test • None of these
The average age of managers in a particular industry is over 35 years old, and we wishe to prove this. The null hypothesis to conduct a statistical test on this theory would be: the population mean is ˃ 35, or the population mean is ≤ 35 or the population mean = 35 or the population mean is ≥ 35.
Not sure how to start or do
12: One researcher estimated that smoking reduces the sense of smell. The mean of the odor test for non-smokers is μ=18.4. The following scores were obtained by giving the same odor test to an unbiased sample of a cigarette smokers: 16 14 19 17 16 17 15 18 19 12 14 18 a) Please set up the Ho and Ha hypotheses.
7.55 What is wrong? In each of the following situations, identify what is wrong and then either explain why it is wrong or change the wording of the statement to make it true. (a) A researcher wants to test Ho: x₁= x₂ versus the two- sided alternative Ha: X₁ X₂. (b) A study recorded the IQ scores of 100 college freshmen. The scores of the 56 males in the study were compared with the scores of all 100 freshmen using the two-sample methods of this section. (c) A two-sample t statistic gave a P-value of 0.94. From this, we can reject the null hypothesis with 90% confidence. (d) A researcher is interested in testing the one-sided alternative Ha: ₁ <₂. The significance test gave t = 2.15. Because the P-value for the two-sided alternative is 0.036, he concluded that his P-value was 0.018.
A researcher developing scanners to search for hidden weapons at airports has concluded that a new scanner is significantly better than the current scanner. He made his decision based on a test using a = 0.05. Would he have made the same decision at a = 0.20? How about α = 0.01? Explain. Select the statement relating decision making to values of a. O A. His decision would have been the same for a = 0.01 but may have been different for a = 0.20. O B. His decision would have been the same for α = 0.20 but may have been different for α = 0.01. O C. His decision may have been different for both α = 0.01 and α = 0.20. O D. His decision would have been the same for both α = 0.01 and α=0.20.

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