60 50 40 30 20 10 53.5 57.5 61.5 65.5 69.5 73.5 77.5 815 Exam Scores Range Frequency Below 61.5 12 61.5-65.5 30 65.5-69.5 69 69.5-73.5 59 27 73.5-77.5 Above 77.5 3 The graph and table above show results from the same random sample of 200 exam scores. At a 10% Le of Significance, test to see if the data fits a normal distribution with mean µ = 69.5 and standard deviation o = 4. To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within two standard deviations, the rest beyond two standard deviations. Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories. 1. The hypotheses are : O Ho:Exam scores are not normally distributed Ha:Exam scores are normally distributed Ho:Exam scores are normally distributed Ha:Exam scores are not normally distributed Frequency
60 50 40 30 20 10 53.5 57.5 61.5 65.5 69.5 73.5 77.5 815 Exam Scores Range Frequency Below 61.5 12 61.5-65.5 30 65.5-69.5 69 69.5-73.5 59 27 73.5-77.5 Above 77.5 3 The graph and table above show results from the same random sample of 200 exam scores. At a 10% Le of Significance, test to see if the data fits a normal distribution with mean µ = 69.5 and standard deviation o = 4. To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within two standard deviations, the rest beyond two standard deviations. Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories. 1. The hypotheses are : O Ho:Exam scores are not normally distributed Ha:Exam scores are normally distributed Ho:Exam scores are normally distributed Ha:Exam scores are not normally distributed Frequency
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Topic Video
Question
![60
50
40
30
20
10
53.5 57.5 61.5 65.5 69.5 73.5 77.5 815
Exam Scores
Range
Frequency
Below 61.5
12
61.5-65.5
30
65.5-69.5
69
69.5-73.5
59
73.5-77.5
27
Above 77.5
3
The graph and table above show results from the same random sample of 200 exam scores. At a 10% Level
of Significance, test to see if the data fits a normal distribution with mean µ = 69.5 and standard
deviation o = 4.
To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within two
standard deviations, the rest beyond two standard deviations.
Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories.
1. The hypotheses are :
O Ho:Exam scores are not normally distributed
Ha:Exam scores are normally distributed
O Ho:Exam scores are normally distributed
Ha:Exam scores are not normally distributed
Kɔuənbəs](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F553bd1e7-affe-41c6-b49f-9cdf1bae2e9b%2F1226d361-214e-4442-862c-4c4efd5a01eb%2Fobpr3rn_processed.png&w=3840&q=75)
Transcribed Image Text:60
50
40
30
20
10
53.5 57.5 61.5 65.5 69.5 73.5 77.5 815
Exam Scores
Range
Frequency
Below 61.5
12
61.5-65.5
30
65.5-69.5
69
69.5-73.5
59
73.5-77.5
27
Above 77.5
3
The graph and table above show results from the same random sample of 200 exam scores. At a 10% Level
of Significance, test to see if the data fits a normal distribution with mean µ = 69.5 and standard
deviation o = 4.
To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within two
standard deviations, the rest beyond two standard deviations.
Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories.
1. The hypotheses are :
O Ho:Exam scores are not normally distributed
Ha:Exam scores are normally distributed
O Ho:Exam scores are normally distributed
Ha:Exam scores are not normally distributed
Kɔuənbəs
![2. This is a
leftO rightO two o tailed test; d.f. = 5
3a. The STS (to 2 decimals) is x =
3b. The P-value (to 3 decimals) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F553bd1e7-affe-41c6-b49f-9cdf1bae2e9b%2F1226d361-214e-4442-862c-4c4efd5a01eb%2F0przkph_processed.png&w=3840&q=75)
Transcribed Image Text:2. This is a
leftO rightO two o tailed test; d.f. = 5
3a. The STS (to 2 decimals) is x =
3b. The P-value (to 3 decimals) =
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