The tennis player strikes the ball at A with a horizontal velocity, and it just clears the net (passes above the net) at point B. a) Determine the initial velocity at point A ( s) b) Find the distance s where the ball hits the ground at C В 7.5 ft C 3 ft S 21 ft

The tennis player strikes the ball at A with a horizontal velocity, and it just clears the net (passes above the net) at point B. a) Determine the initial velocity at point A ( s) b) Find the distance s where the ball hits the ground at C В 7.5 ft C 3 ft S 21 ft

Name: The tennis player strikes the ball at A with a horizontal velocity, a
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: The tennis player strikes the ball at A with a horizontal velocity, and it just clears the net (passesabove the net) at point B.a) Determine the initial velocity at point A (4)b) Find the distance s where the ball hits the ground at CВ7.5 ft3 ft21 f

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

In a baseball game, the batboy , after hitting the ball runs towards the first base, a distance of 27 m away. The ball was caught by the short stop team member 30 m away from the first base after 1 second and throws immeiately the ball to the first base at a velocity of 45 m/s. Assume a horizontal path of the ball. What is the minimum velocity the batboy should run o reach safe the first base
Dominador, who is standing on the edge of an 80-m tall cliff facing the sea, kicks a ball horizontally at a speed of 13.01 m/s. How far from the base of the cliff will the ball hit the sea water? Let be the initial vertic
A ball is thrown horizontally with an initial velocity Vo. Determine the values V. if it hits point B or point C. A 3 1+14 B Ift C I'm
A ball is kicked from the ground at point 0 with an initial velocity vo = 20 m/s that makes an angle 0 = 30° with the horizontal. This ball reaches its maximum height at point A and then returns to the ground at point B as shown in the figure. (g = 10m/s²) The time taken by the ball to reach the maximum height at point A (toa) is equal to: A. 0.5s B Is Vo hmax C. 15 s D 2s E 25 s F5 F6 PriSc Insert Del FB F9 F10 F11 F12 & 6 7 + II
A vehicle is on a hill that has a 20 degree angle below the horizonal. An irresponsible driver leaves the vehicle in neutral. The vehicle rolls backwards toward the edge of he cliff. The acceleration is 2.37 m/s^2 and the distance traveled is 55m before the vehicle reaches the edge of the cliff. The cliff is 30m high. a) How much time will the vehicle be in the air fter leaving the cliff? b) How far horizontally will the vehicle be away from the cliff when it lands?
A frog leaps off the ground at an angle of 20 degrees to the horizontal. It's in the air for .84 seconds before landing at the same height from which it took off. a) Given this leap, what is the initial velocity of the frog? b) How far does the frog jump?
A cannonball is shot with an initial speed of 30.0 m/s and 25.0º angle below horizontal from a height of 12.0 m. How far can the cannonball go horizontally when it lands on the ground, in meters? Use g = 10.0 m/s2. (Hint: Clearly label quantities along x- and y- components and write down all steps.)
Problem For a projectile lunched with an initial velocity of vo at an angle of e (between O and 90), a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of e gives the highest maximum height? Solution The components of vo are expressed as follows: Vinitial-x= vocos(e) Vinitial-y = vosin(e) a) Let us first find the time it takes for the projectile to reach the maximum height. Using Vfinal-y = Vinitial-y * ayt since the y-axis velocity of the projectile at the maximum height is Vfinal-y= Then, = Vinitial-y +ayt Substituting the expression of vinitial-y and ay = -g results to the following Thus, the time to reach the maximum height is Imax-height We will use this time to the equation yfinal - Yinitial = Vinitialyt+ (1/2)a,2 if we use the time taken to reach the maximum height, therefore, the displacement will yield the maximum height, so hmax = Vinitial-y + (1/2lay? substituting the Vinitial-y expression above, results to the following…
Plz answer correctly asap
8. You fire a ball with an initial speed of vo at an angle o above the surface of an incline, which is itself inclined at an angle 6 above the horizontal. a) Find the distance, measured along the incline, from the launch point to the point when the ball strikes the incline.
A ball thrown down the inclined strikes it at an inclined distance of 75m If the ball rises to a maximum height of 20m above the point of release. Compute the initial velocity and the projectile angle from horizontal (Say slope ofinclined is is 1V:3H) Choose the correct answer: a. 30m/sb. 54 3degc. 16.67m/sd. 24.4m/se. 43.2degf. 33.3degg.17.4m/sh. 45degi. 20.7m/sj. 23.6deg
A projectile is fired with an initial speed of 25 m/s at an angle θ reaches a maximum height of 18m. The angle θ is given by a.) θ = 25.8o b.) θ = 75.3o c.) θ = 48.7o d.) θ = 30o