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The task is to to transfer the fluid from the source towards the tank (TANK A) lying on an elevated platform as shown. The goal is to fill up that 16.49 m by 2.23 m by 6.36 m tank (TANK A) within 11.5 mins (from empty to full). Your budget is limited to 605,000 pesos. Head loss on pipe due to friction is 1.23 meters per 1 meter of pipe.

The task is to to transfer the fluid from the source towards the tank (TANK A) lying on an elevated platform as shown. The goal is to fill up that 16.49 m by 2.23 m by 6.36 m tank (TANK A) within 11.5 mins (from empty to full). Your budget is limited to 605,000 pesos. Head loss on pipe due to friction is 1.23 meters per 1 meter of pipe.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The task is to to transfer the fluid from the source towards the tank (TANK A) lying on an elevated platform as shown. The goal is to fill up that 16.49 m by 2.23 m by 6.36 m tank (TANK A) within 11.5 mins (from empty to full). Your budget is limited to 605,000 pesos. Head loss on pipe due to friction is 1.23 meters per 1 meter of pipe. Because it's Fluid Machinery and not Engineering Economics, it's ok for your design to exceed the budget BUT YOU HAVE TO JUSTIFY IT. The pictures I will post is the guide to answer Its okay if the answer is computerized
4G+ 12:17 y eltl ll 38 Use this sample answer for your reference. Makikita na iba yung given sa sample, kasi for reference lang siya. Try not to copy everything ok? Ne e gad 13 yang nakgyni vetcal hypokne tayo na 150 tent veticalcomponnt woud be anund 12m big abinin the vetca dtarce ng dacturge ppe yang vot haud NOT DE LES TAN 1201 Bee dea vericaeghtng ction ppe tyung da ances yause charge Thas bcanekng y 1.5m 0.23 m- TANK A Ø = 15 cm Ao, o be rete, ean may aaravetc ppe ine atametes ang taa an nggom at nkad a nga ataces y nakita kata This tasn Mang es sadgn Kya wenle ten 33.24° Option A pump Ø = 35 cm 0.3m 0.5m THIS IS AREA IS RESTRICTED. BAWAL SOURCE: SG = 1.55 4.28 m PADAANIN ANG MGA PIPES SA AREA NA ITO. Ok JUSTIFICATION FOR NPSH V (2)(3)(4) = 0.02 m3 =-= 20(60) sec PVi+z, + h - hyt + z, + hy - h (0.352n NPSH = pg 2g Q = VA - 0.02 = v - V = 0.21 4 h, = 0.3 (0.2 + 0.3) = 0.15 P V? NPSH = ++z, + h, – hy1 pg 29 101325 0.212 NPSH = + 0.2 + 0.15 - 8.6 1000(9.8) 2(9.8) NPSH = 2.09 m 7 ft ok 15.32 m
Transcribed Image Text:4G+ 12:17 y eltl ll 38 Use this sample answer for your reference. Makikita na iba yung given sa sample, kasi for reference lang siya. Try not to copy everything ok? Ne e gad 13 yang nakgyni vetcal hypokne tayo na 150 tent veticalcomponnt woud be anund 12m big abinin the vetca dtarce ng dacturge ppe yang vot haud NOT DE LES TAN 1201 Bee dea vericaeghtng ction ppe tyung da ances yause charge Thas bcanekng y 1.5m 0.23 m- TANK A Ø = 15 cm Ao, o be rete, ean may aaravetc ppe ine atametes ang taa an nggom at nkad a nga ataces y nakita kata This tasn Mang es sadgn Kya wenle ten 33.24° Option A pump Ø = 35 cm 0.3m 0.5m THIS IS AREA IS RESTRICTED. BAWAL SOURCE: SG = 1.55 4.28 m PADAANIN ANG MGA PIPES SA AREA NA ITO. Ok JUSTIFICATION FOR NPSH V (2)(3)(4) = 0.02 m3 =-= 20(60) sec PVi+z, + h - hyt + z, + hy - h (0.352n NPSH = pg 2g Q = VA - 0.02 = v - V = 0.21 4 h, = 0.3 (0.2 + 0.3) = 0.15 P V? NPSH = ++z, + h, – hy1 pg 29 101325 0.212 NPSH = + 0.2 + 0.15 - 8.6 1000(9.8) 2(9.8) NPSH = 2.09 m 7 ft ok 15.32 m
4G+ 12:17 yI lll ll 38 JUSTIFICATION Since incompressible ang fluid, ang volume flow rate sa discharge ay kaparehas ng volume flow FOR OUTPUT V_ (2)(3)(4) 20(60) Q = = 0.02 sec rate sa suction. H, = 2 pg + z2 + hy 78.352m Q = VA - 0.02 = V 4 - V = 0.21 h, = 0.3 (0.5 + 13 + 1.5) = 4.5 P v? H2 = + z1 + h, - hy1 pg 2g 0.212 101325 + 3500 H2 = + 13 + 4.5 1000(9.8) 2(9.8) H2 = = 28.20m 92.5 ft ok Parameters: Care 77 M Inp d 00 Set Volume Flow Rate: 0.02 m/sec TA rien del Speed 349.2 galimin 120 35 NPSH: 7 ft Hy: 75 ft 100 E 30 D Pwede ang Option C, D and E if 'lI ignore NPSH. Kaso hindi pwede, so I have to make adjustments on the suction side or taasan ang volume flow rate. (This could happen on your first try. If this happens, make adjustments. -25 20 60 15 Kung wala talaga, choose Option F. sbosed on e -10 20 100 200 300 00 S00 600 700 S00 900 1000 Flow in gallons per minute ok
Transcribed Image Text:4G+ 12:17 yI lll ll 38 JUSTIFICATION Since incompressible ang fluid, ang volume flow rate sa discharge ay kaparehas ng volume flow FOR OUTPUT V_ (2)(3)(4) 20(60) Q = = 0.02 sec rate sa suction. H, = 2 pg + z2 + hy 78.352m Q = VA - 0.02 = V 4 - V = 0.21 h, = 0.3 (0.5 + 13 + 1.5) = 4.5 P v? H2 = + z1 + h, - hy1 pg 2g 0.212 101325 + 3500 H2 = + 13 + 4.5 1000(9.8) 2(9.8) H2 = = 28.20m 92.5 ft ok Parameters: Care 77 M Inp d 00 Set Volume Flow Rate: 0.02 m/sec TA rien del Speed 349.2 galimin 120 35 NPSH: 7 ft Hy: 75 ft 100 E 30 D Pwede ang Option C, D and E if 'lI ignore NPSH. Kaso hindi pwede, so I have to make adjustments on the suction side or taasan ang volume flow rate. (This could happen on your first try. If this happens, make adjustments. -25 20 60 15 Kung wala talaga, choose Option F. sbosed on e -10 20 100 200 300 00 S00 600 700 S00 900 1000 Flow in gallons per minute ok
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