What is the P-value?P-value =Should the null hypothesis be rejected?(Round to three decimal places as needed.)O A. Yes, reject Ho. There is not sufficient evidence at the α = 0.01 level of significance to conclude that X and Y are dependent because the P-value < x.B. Yes, reject Ho. There is not sufficient evidence at the x = 0.01 level of significance to conclude that X and Y are dependent because the P-value > α.O C. No, do not reject Ho. There is not sufficient evidence at the α = 0.01 level of significance to conclude that X and Y are dependent because the P-value > α.O D. No, do not reject Ho. There is sufficient evidence at the x = 0.01 level of significance to conclude that X and Y are dependent because the P-value < α. The table to the right contains observed values and expected values in parentheses for two categorical variables, X and Y, where variable X has three categories and variable Y has two categories.Use the table to complete parts (a) and (b) below.(a) Compute the value of the chi-square test statistic.2x² ==(Round to three decimal places as needed.)(b) Test the hypothesis that X and Y are independent at the α = 0.01 level of significance.O A. Ho: The Y category and X category have equal proportions.H₁:: The proportions are not equal.B. Ho: The Y category and X category are independent.H₁: The Y category and X category are dependent.O C. Ho: The Y category and X category are dependent.H₁: The Y category and X category are independent.O D. Ho: x = Ex and μy = EyHyH₁: Hx #Ex or Hy # EyY₁Y₂X₂X345 49X₁33(34.82) (46.43)(45.75)1818(16.18) (21.57) (21.25)23□

The observed (O) and expected (E) frequencies are: O E 33 34.82 45 46.43 49 45.75 18…

Answered: The table to the right contains…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁:µm > µF H₁:PM > pF Ho: PM = PF H₁:PM
Test the claim that the mean GPA of night students is significantly different than 2.7 at the 0.04 significance level.The null and alternative hypotheses would be: H0:μ=2.7H0:μ=2.7H1:μ≠2.7H1:μ≠2.7 H0:p=0.675H0:p=0.675H1:p>0.675H1:p>0.675 H0:p=0.675H0:p=0.675H1:p<0.675H1:p<0.675 H0:μ=2.7H0:μ=2.7H1:μ>2.7H1:μ>2.7 H0:p=0.675H0:p=0.675H1:p≠0.675H1:p≠0.675 H0:μ=2.7H0:μ=2.7H1:μ<2.7H1:μ<2.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.66 with a standard deviation of 0.16The p-value is: (to 3 decimals)The positive significance level is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level.The null and alternative hypotheses would be: H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:μ=2.4H0:μ=2.4H1:μ≠2.4H1:μ≠2.4 H0:μ=2.4H0:μ=2.4H1:μ>2.4H1:μ>2.4 H0:p=0.6H0:p=0.6H1:p<0.6H1:p<0.6 H0:μ=2.4H0:μ=2.4H1:μ<2.4H1:μ<2.4 H0:p=0.6H0:p=0.6H1:p>0.6H1:p>0.6 The test is: right-tailed left-tailed two-tailed Based on a sample of 31 people, the sample mean GPA was 2.36 with a standard deviation of 0.16The p-value is: (to 3 decimals)The positive significance level is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
review(8a): Identify the test statistic used for the ANOVA prodcedure and how it is calculated (a) the test statistic is F and is calculated by finding the difference between group means (b)the test staitistic is z and is calculated by finding the mean z score between groups. (c) the test statistic is F and is the ratio of the variation getween groups to the variation within groups. (d) the test statistic is z and is the ratio of the mean within a group to the variation between groups
Professor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the mean score of the population? What is the mean score of the sample? Is this test one-tailed or two-tailed? Why?
The table to the right contains observed values and expected values in parentheses for two categorical variables, X and Y, where variable X has three categories and variable Y has two categories. Use the table to complete parts (a) and (b) below. (a) Compute the value of the chi-square test statistic. x = (Round to three decimal places as needed.) Y₁ Y₂ X1 X₂ X3 32 40 50 (33.77) (42.05) (46.18) 21 17 17 (15.23) (18.95)(20.82)
Please answer the question in the image
Test the claim that the mean GPA of night students is significantly different than 2 at the 0.01 significance level. The null and alternative hypothesis would be: Но: р > 0.5 Нo: 2 H1:p > 0.5 H1:µ # 2 H1:p+ 0.5 H1:µ 2 The test is: right-tailed left-tailed two-tailed Based on a sample of 55 people, the sample mean GPA was 2.05 with a standard deviation of 0.03 The p-value is: (to 2 decimals)
Scenario: I'm interested in whether there is a relationship between Team (A vs. B) and Outcome (Good vs. Bad). Below are the data. Test the null hypothesis that the categories are independent. α= .05. Team A Team B Good Outcome fo = 75 fe = fo = 45 fe = Bad Outcome fo = 25 fe = fo = 5 fe = The expected frequency, fe , for the Team A X Good Outcome category = _____
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be: Ho: PNPD Ho: UN ≤ HD Ha:N HD Ha:μN > HD The test is: right-tailed two-tailed left-tailed O Ho: PNPD Ho: PNPD Ho: PN Ha:PN PD O
Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significance level. The null and alternative hypothesis would be: Ho: µ 2 2.5 Ho:p 0.625 Ho:p= 0.625 Ho: µ 0.625 H1:p 2.5 H:µ + 2.5 The test is: left-tailed two-tailed right-tailed Based on a sample of 60 people, the sample mean GPA was 2.47 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

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