The table summarizes results from 978 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 59 80 276 563 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was intoxicated. Please enter a decimal to 4 decimal places. Probability=
The table summarizes results from 978 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 59 80 276 563 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was intoxicated. Please enter a decimal to 4 decimal places. Probability=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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![The table below summarizes results from 978 pedestrian deaths that were caused by automobile accidents.
### Pedestrian Deaths
| Driver Intoxicated? | Pedestrian Intoxicated? | | |
|-----------------------------|-------------------------|------------------|------------------|
| | | **Yes** | **No** |
| **Yes** | | **59** | **80** |
| **No** | | **276** | **563** |
If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was intoxicated. Please enter the probability as a decimal to 4 decimal places.
Probability = [Your Answer Here]
### Explanation
In the table:
- The row "Yes" under "Driver Intoxicated?" with columns "Yes" and "No" for "Pedestrian Intoxicated?" respectively denotes:
- 59 pedestrian deaths where both the driver and the pedestrian were intoxicated.
- 80 pedestrian deaths where the driver was intoxicated but the pedestrian was not.
- The row "No" under "Driver Intoxicated?" with columns "Yes" and "No" for "Pedestrian Intoxicated?" respectively denotes:
- 276 pedestrian deaths where the driver was not intoxicated but the pedestrian was.
- 563 pedestrian deaths where neither the driver nor the pedestrian were intoxicated.
To find the probability that the pedestrian was not intoxicated or the driver was intoxicated, you need to sum the relevant cases:
- Pedestrian not intoxicated: 80 + 563 = 643
- Driver intoxicated: 59 + 80 = 139
Since 59 cases where both the driver was intoxicated and the pedestrian was intoxicated are counted in both categories, we need to subtract them to avoid double counting.
The total relevant cases are:
643 + 139 - 59 = 723
The probability is:
\[ \frac{723}{978} = 0.7392 \]
Therefore, the probability that the pedestrian was not intoxicated or the driver was intoxicated is approximately \(0.7392\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbed7ab37-3726-4b83-a741-6ed60a3ee8a9%2F456c4f17-0cad-4341-aa97-ad4ef554cf6a%2Fftomckf_processed.png&w=3840&q=75)
Transcribed Image Text:The table below summarizes results from 978 pedestrian deaths that were caused by automobile accidents.
### Pedestrian Deaths
| Driver Intoxicated? | Pedestrian Intoxicated? | | |
|-----------------------------|-------------------------|------------------|------------------|
| | | **Yes** | **No** |
| **Yes** | | **59** | **80** |
| **No** | | **276** | **563** |
If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was intoxicated. Please enter the probability as a decimal to 4 decimal places.
Probability = [Your Answer Here]
### Explanation
In the table:
- The row "Yes" under "Driver Intoxicated?" with columns "Yes" and "No" for "Pedestrian Intoxicated?" respectively denotes:
- 59 pedestrian deaths where both the driver and the pedestrian were intoxicated.
- 80 pedestrian deaths where the driver was intoxicated but the pedestrian was not.
- The row "No" under "Driver Intoxicated?" with columns "Yes" and "No" for "Pedestrian Intoxicated?" respectively denotes:
- 276 pedestrian deaths where the driver was not intoxicated but the pedestrian was.
- 563 pedestrian deaths where neither the driver nor the pedestrian were intoxicated.
To find the probability that the pedestrian was not intoxicated or the driver was intoxicated, you need to sum the relevant cases:
- Pedestrian not intoxicated: 80 + 563 = 643
- Driver intoxicated: 59 + 80 = 139
Since 59 cases where both the driver was intoxicated and the pedestrian was intoxicated are counted in both categories, we need to subtract them to avoid double counting.
The total relevant cases are:
643 + 139 - 59 = 723
The probability is:
\[ \frac{723}{978} = 0.7392 \]
Therefore, the probability that the pedestrian was not intoxicated or the driver was intoxicated is approximately \(0.7392\).
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