The table summarizes results from pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 61 75 232 620 If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were intoxicated. Report the answer rounded to four decimal place accuracy.
The table summarizes results from pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 61 75 232 620 If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were intoxicated. Report the answer rounded to four decimal place accuracy.
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Author:Amos Gilat
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![### Pedestrian Death Statistics from Automobile Accidents
The table below summarizes results from pedestrian deaths that were caused by automobile accidents:
#### Pedestrian Deaths
| Driver Intoxicated? | Pedestrian Intoxicated? | Yes | No |
|----------------------|-------------------------|-----|-----|
| Yes | Yes | 61 | 75 |
| No | Yes | 232 | 620 |
**Question:**
If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were intoxicated. Report the answer rounded to four decimal place accuracy.
**Explanation of Graphs/Diagrams:**
The table is a contingency table that shows the relationship between two categorical variables: whether the driver was intoxicated (Yes/No) and whether the pedestrian was intoxicated (Yes/No). Each cell inside the table represents the frequency of occurrences for each combination of the variables. For instance, there are 61 occurrences where both the driver and the pedestrian were intoxicated, and 620 occurrences where neither the driver nor the pedestrian were intoxicated.
To calculate the probability of two randomly selected pedestrian deaths both involving intoxicated pedestrians:
1. Compute the total number of pedestrian deaths involving intoxicated pedestrians: 61 (driver intoxicated) + 232 (driver not intoxicated) = 293
2. Compute the total number of pedestrian deaths: 61 + 75 + 232 + 620 = 988
3. Calculate the probability that both randomly selected deaths involved intoxicated pedestrians:
- The probability of selecting one intoxicated pedestrian death is 293/988.
- The probability of then selecting a second intoxicated pedestrian death is (293-1)/987 since one has already been chosen.
- Multiply these probabilities: P = (293/988) * (292/987).
By performing the calculations and rounding to four decimal places, the answer can be filled in the provided answer box.
**Answer Box:**
[________]
This table and subsequent analysis help in understanding the influence of intoxication on pedestrian deaths in automobile accidents.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbed7ab37-3726-4b83-a741-6ed60a3ee8a9%2F842a2881-85bd-4c3e-8038-5fe4122edd6d%2Fvuher8n_processed.png&w=3840&q=75)
Transcribed Image Text:### Pedestrian Death Statistics from Automobile Accidents
The table below summarizes results from pedestrian deaths that were caused by automobile accidents:
#### Pedestrian Deaths
| Driver Intoxicated? | Pedestrian Intoxicated? | Yes | No |
|----------------------|-------------------------|-----|-----|
| Yes | Yes | 61 | 75 |
| No | Yes | 232 | 620 |
**Question:**
If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were intoxicated. Report the answer rounded to four decimal place accuracy.
**Explanation of Graphs/Diagrams:**
The table is a contingency table that shows the relationship between two categorical variables: whether the driver was intoxicated (Yes/No) and whether the pedestrian was intoxicated (Yes/No). Each cell inside the table represents the frequency of occurrences for each combination of the variables. For instance, there are 61 occurrences where both the driver and the pedestrian were intoxicated, and 620 occurrences where neither the driver nor the pedestrian were intoxicated.
To calculate the probability of two randomly selected pedestrian deaths both involving intoxicated pedestrians:
1. Compute the total number of pedestrian deaths involving intoxicated pedestrians: 61 (driver intoxicated) + 232 (driver not intoxicated) = 293
2. Compute the total number of pedestrian deaths: 61 + 75 + 232 + 620 = 988
3. Calculate the probability that both randomly selected deaths involved intoxicated pedestrians:
- The probability of selecting one intoxicated pedestrian death is 293/988.
- The probability of then selecting a second intoxicated pedestrian death is (293-1)/987 since one has already been chosen.
- Multiply these probabilities: P = (293/988) * (292/987).
By performing the calculations and rounding to four decimal places, the answer can be filled in the provided answer box.
**Answer Box:**
[________]
This table and subsequent analysis help in understanding the influence of intoxication on pedestrian deaths in automobile accidents.
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