The table lists common half-reactions along with the standard reduction potential associated with each half-reaction. These standard reduction potentials are all relative to some standard.What is the standard (zero point)?If is positive for a half-reaction, what does it mean?If is negative for a half-reaction, what does it mean? Which species in table is most easily reduced? Least easily reduced? If the reverse of the half-reactions in the table are the oxidation half-reactions, how are standard oxidation potentials determined TABLE 17.1Standard Reduction Potentials at 25°C (298 K) for Many Common Half-ReactionsHalf-ReactionE* (V)g° (V)Half-ReactionF; + 2e + 2FAg* +e + Ag"Co +e + CoHO, + 2H + 2e"Ce*" + e → Ce"O, + 2H,0 + 4e 40HCu* + 2e - CuHg Cl; + 2e - 2Hg + 20AgCl +e + Ag + Cso + 4H' + 2e" + H,SO, + H,0Cu* + e Cu"2.870.401.990.341.821.780.27• 2H,00.221.700.20PBO, + 4H* + So,- + 2e → PhSO, + 2H0MnO, + 4H" + 3e → MnO, + 2H,02e + 2H* + 10, 10, + H,0MnO, + 8H* + 5e + Mn* + 4H,0Au+ + 3e AuPbO, + 4H* + 2e + Pb* + 2H0C, + 2e 2CICr,0, + 14H + 6e¯ → 2Cr" + 7H;OO, + 4H" + 4e 2H,0MnO, + 4H* + 2e → Mn* + 2H,010, + 6H" + 5e -Br, + 2e 2BrVO," + 2H + e Vo + H,OAuCl, + 3e → Au + 4CINO, + 4H* + 3e → NO + 2H,0C1O, +e → CIO,2Hg** + 2e -Ag +e AgHg,* + 2e → 2HgFe* + e → Fe+O, + 2H* + 2e H,O,MnO, +e - MnO,Iz + 2e 21Cu" +e → Cu1.690.162H* + 2e HzFe* + 3e- FePb* + 2eSn* + 2e - SnNi** + 2e NiPhSO, + 2e - Pb + SoCd** + 2e CdFe* + 2e -→ FeCr* +e" Cr*Cr* + 3e CrZn + 2e Zn2H,0 + 2e → Hạ + 20HMn** + 2e - MnAl" + 3e AlH2 + 2e 2HMg* + 2e - MgLa + 3e La1.680.001.60-0.0361.51- Pb-0.131.50-0.141.46-0.231.36-0.351.33-0.401.23-0.441.21-0.50→ Įl; + 3H¿01.20-0.731.09-0.761.00-0.830.99-1.180.96-1.660.954-2.230.91-2.370.80-2.370.80Na* +e + Na-2.71Ca + 2e CaBa* + 2e → BaK* +e + KLi" +e + Li0.77-2.760.68-2.900.56-2.920.54-3.050.52

Always the electrochemical reaction is expressed in form where the reactant is reduced to another…

Answered: The table lists common half-reactions…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

100%

The table lists common half-reactions along with the standard reduction potential associated with each half-reaction. These standard reduction potentials are all relative to some standard.

What is the standard (zero point)?
If is positive for a half-reaction, what does it mean?
If is negative for a half-reaction, what does it mean?
Which species in table is most easily reduced? Least easily reduced?
If the reverse of the half-reactions in the table are the oxidation half-reactions, how are standard oxidation potentials determined

TABLE 17.1
Standard Reduction Potentials at 25°C (298 K) for Many Common Half-Reactions
Half-Reaction
E* (V)
g° (V)
Half-Reaction
F; + 2e + 2F
Ag* +e + Ag"
Co +e + Co
HO, + 2H + 2e"
Ce*" + e → Ce"
O, + 2H,0 + 4e 40H
Cu* + 2e - Cu
Hg Cl; + 2e - 2Hg + 20
AgCl +e + Ag + C
so + 4H' + 2e" + H,SO, + H,0
Cu* + e Cu"
2.87
0.40
1.99
0.34
1.82
1.78
0.27
• 2H,0
0.22
1.70
0.20
PBO, + 4H* + So,- + 2e → PhSO, + 2H0
MnO, + 4H" + 3e → MnO, + 2H,0
2e + 2H* + 10, 10, + H,0
MnO, + 8H* + 5e + Mn* + 4H,0
Au+ + 3e Au
PbO, + 4H* + 2e + Pb* + 2H0
C, + 2e 2CI
Cr,0, + 14H + 6e¯ → 2Cr" + 7H;O
O, + 4H" + 4e 2H,0
MnO, + 4H* + 2e → Mn* + 2H,0
10, + 6H" + 5e -
Br, + 2e 2Br
VO," + 2H + e Vo + H,O
AuCl, + 3e → Au + 4CI
NO, + 4H* + 3e → NO + 2H,0
C1O, +e → CIO,
2Hg** + 2e -
Ag +e Ag
Hg,* + 2e → 2Hg
Fe* + e → Fe+
O, + 2H* + 2e H,O,
MnO, +e - MnO,
Iz + 2e 21
Cu" +e → Cu
1.69
0.16
2H* + 2e Hz
Fe* + 3e- Fe
Pb* + 2e
Sn* + 2e - Sn
Ni** + 2e Ni
PhSO, + 2e - Pb + So
Cd** + 2e Cd
Fe* + 2e -→ Fe
Cr* +e" Cr*
Cr* + 3e Cr
Zn + 2e Zn
2H,0 + 2e → Hạ + 20H
Mn** + 2e - Mn
Al" + 3e Al
H2 + 2e 2H
Mg* + 2e - Mg
La + 3e La
1.68
0.00
1.60
-0.036
1.51
- Pb
-0.13
1.50
-0.14
1.46
-0.23
1.36
-0.35
1.33
-0.40
1.23
-0.44
1.21
-0.50
→ Įl; + 3H¿0
1.20
-0.73
1.09
-0.76
1.00
-0.83
0.99
-1.18
0.96
-1.66
0.954
-2.23
0.91
-2.37
0.80
-2.37
0.80
Na* +e + Na
-2.71
Ca + 2e Ca
Ba* + 2e → Ba
K* +e + K
Li" +e + Li
0.77
-2.76
0.68
-2.90
0.56
-2.92
0.54
-3.05
0.52

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions