4b. The conclusion is:There is sufficient evidence to conclude that the mean ages in at least two of the states aredifferentThere is insufficient evidence to conclude that the mean ages in at least two of the states aredifferentO There is sufficient evidence to conclude that the mean ages in the states are the sameThere is insufficient evidence to conclude that the mean ages in the states are the sameSubmit QuestionMacBook Air Question 14MississippiOregonArizonaNew MexicoKansas41414348433542473948414343484945434539394639414239The table gives the ages of randomly chosen people from 5 different statesAt a = 0.05, determine whether there is a difference in mean ages.1. Thehypothesis is Ho:Hi = 42 = H3 = 4 = µ5O µ1 = 42 = H3O H1 = µ2 = H3 = H42. This is a right tailed test with:d.f.n =and d.f.d =3a. The STS (to 2 decimals) is F =3b. The P-value (to 3 decimals) is:4a. At a = 0.05, the decision is:O Accept HoO Reject HoO Accept HaO Do not reject HoMacBook Air

Name: 4b. The conclusion is:There is sufficient evidence to conclude that t
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Description: 4b. The conclusion is:There is sufficient evidence to conclude that the mean ages in at least two of the states aredifferentThere is insufficient evidence to conclude that the mean ages in at least two of the states aredifferentO There is sufficient

Given data, Mississippi Oregon Arizona New Mexico Kansas 41 41 43 48 43 35 42 47 39 48 41…

Math

Statistics

The table gives the ages of randomly chosen people from 5 different states At a = 0.05, determine whether there is a difference in mean ages. %3D 1. The null hypothesis is Ho: Hi = H2 = Hz = H4 = H5 %3D O pi = #2 = H3 OH1 = 42 = H3 = H4 %3D 2. This is a right tailed test with: d.f.n = and d.f.d = 3a. The STS (to 2 decimals) is F = %3D 3b. The P-value (to 3 decimals) is: 4a. At a = 0.05, the decision is: O Accept Ho O Reject Ho O Accept Ha Do not reject Ho

The table gives the ages of randomly chosen people from 5 different states At a = 0.05, determine whether there is a difference in mean ages. %3D 1. The null hypothesis is Ho: Hi = H2 = Hz = H4 = H5 %3D O pi = #2 = H3 OH1 = 42 = H3 = H4 %3D 2. This is a right tailed test with: d.f.n = and d.f.d = 3a. The STS (to 2 decimals) is F = %3D 3b. The P-value (to 3 decimals) is: 4a. At a = 0.05, the decision is: O Accept Ho O Reject Ho O Accept Ha Do not reject Ho

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This output represents the hypothesis test that the average age at first pregnancy of women diagnosed with breast cancer is different depending on whether or not metastases are present (yes or no) at the time of breast cancer diagnosis.