The table below shows the lab result of the sieve analysis of a soil sample Diameter (mm) Percent Passing, % 100 4.750 2.000 0.850 94.5 86.3 0.425 74.1 0.250 54.9 0.180 38.1 0.150 9.3 0.075 1.7 a. Calculate the coefficient of gradation of the soil sample. Use logarithmic interpolation b. Classify the soil according to USCS

The table below shows the lab result of the sieve analysis of a soil sample Diameter (mm) Percent Passing, % 100 4.750 2.000 0.850 94.5 86.3 0.425 74.1 0.250 54.9 0.180 38.1 0.150 9.3 0.075 1.7 a. Calculate the coefficient of gradation of the soil sample. Use logarithmic interpolation b. Classify the soil according to USCS

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Percent Passing 4 4.760 100 6 2.380 91 10 2.000 88 20 0.840 76 40 0.420 55 60 0.250 50 100 0.150 47 200 0.075 46 Characteristics of No. 40 Fraction LL 50 PL 34
Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30
A sieve analysis of a soil sample of weight (400 g) was performed and the results were as follows. Required 1-Find the% passing and plot the gradient gradient. 2-Find the regularity coefficient and the Cu gradient
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
Soil
Geotechnical Engineering
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 89% No.200 = 65% Liquid Limit= 44 Plastic Limit = 23
SG is 2.66 and temperature is 18 degrees celcius
2. For the given data, shows a sieve analysis of soil samples A,B, and C. Diameter Soil A Soil B Soil C Sieve No. (mm) %Passing %Passing %Passing # 4 4.760 90 100 100 a. Classify soil sample A using USCS Method b. Classify soil sample B using USCS Method c. Classify soil sample C using # 8 2.380 64 90 100 #10 2.000 54 77 98 #20 0.840 34 59 92 # 40 0.420 22 51 84 #60 0.250 17 42 79 USCS Method #100 0.149 9. 35 70 #200 0.074 4 33 63 LL 46 47 PL 29 24
Calculate K for the soil tested in the figure. Assume the cross-sectional area of the sample is 14 cm² and the area of the standpipe is 2cm². The time of test = 15 min. All dimensions shown are in mm. D 270 T 200 soil 70 580 310
From the given data, shows a sieve analysis of soil samples A, B and C. SOIL SAMPLE B PERCENT PASSING 100 90 77 59 51 42 35 33 Sieve No. Diam. (mm) # 4 # 8 #10 #20 #40 #60 #100 # 200 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Characteristics of 40 Fraction 90 100 64 54 34 22 17 9. 100 98 92 84 79 70 63 LL PL 46 29 47 24 Classify the soil sample A using USCS Method Classify the soil sample B using AASHTO Method a Classify the soil sample C using AASHTO Method,