Answered: The t- distribution for developing a…

Name: The t- distribution for developing a confidence interval for a mean h
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: The t- distribution for developing a confidence interval for a mean hasdegrees of freedom.A.n - 2B.nC.n +1D.n -1

Math

Statistics

The t- distribution for developing a confidence interval for a mean has degrees of freedom. A.n - 2 B.n C.n+1 D.n - 1

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Help. How do you find the solution. Where do you start?
[Statistics] How do you find the upper bound of a confidence interval for the difference of means? The data is given below Pollution Group40 116 144 147 126 164 135 1 53 1 45 1 52 1 31 1 38 1 44 1 29 1 45 1 47 134 228 2 36 2 19 2 35 2 37 236 2 39 2 32 225 2 37 2 40 2 44 2 38 2
Use the Empirical Rule to find the following probabilities. It is suggested that you draw a normal curve, label the x-values for 1, 2, and 3 standard deviations from the mean, and write in the probabilities between each
The “Descriptive Statistics” function in Excel … calculates the confidence level using both the t and the z distributions calculates the confidence level using the z distributions calculates the confidence level using the t distributions calculates the confidence level using the chi-square distributions
Suppose you calculate a z-score of -2.2 and the distribution is normal. Then which of the following is a correct interpretation? Group of answer choices None of the above are justified interpretations The observation is about 2.2 standard deviations less than the mean. This means it is less than all but roughly 2.5% of the observations. The observation is about 2.2 times the variance less than the mean. This means it is less than all but roughly 5% of the observations The observation is about 2.2 times the variance less than the mean. This means it is less than all but roughly 2.5% of the observations. The observation is about 2.2 standard deviations less than the mean. This means it is less than all but roughly 5% of the observations.
q47
You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 4 11 11 7 10 7 9 2 8 11 9 4 12 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 13 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.
A random sample of statistics students were asked to estimate the total number of hours they spend watching television in an average week. The responses are recorded in Table. Use this sample data to construct a 98% confidence interval for the mean number of hours statistics students will spend watching television in one week. Assume the population is normally distributed. (Give your answer to 3 decimal places if necessary.) 20 13 1 10 20 0 10 13 16 10 1 17 18 3 9 (?,?)
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 26 5 10 23 14 14 8 19 6 8 12 a. To compute the confidence interval use a ? z or t distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between __and ___visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About __percent of these confidence intervals will contain the true population mean number of visits per patient and about __percent will not contain the true population mean number of visits per patient.
You are interested in finding a 98% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 14 randomly selected college students. Round answers to 3 decimal places where possible. 12 5 7 4 6 9 11 11 9 8 5 9 10 11 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 19 28 12 5 9 8 5 21 20 21 24 9 21 a. To compute the confidence interval use a ____distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between ____ and _____ visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ______percent of these confidence intervals will contain the true population mean number of visits per patient and about_______ percent will not contain the true population mean number of visits per patient.
USE 3 DECIMAL A researcher believes that reading habit of newspaper is decreasing every year. In order to see the true population proportion of people who are reading newspaper s/he collect a randomly selected people on the yearly basis. The following table gives the number of people who do not read newspaper with respect to the years. Construct a 90 % confidence interval for the true population proportion difference of people who are reading newspaper in 2005 and 2010. 20102005 n 12001000 Number of people who do not read newspaper 300 400