**Understanding Probability and Standard Deviation in a Card Game**In this educational scenario, you are playing a card game where the probability that you will win a game is \( p = 0.73 \).1. **Most Likely Number of Wins:** If you play the game 282 times, what is the most likely number of wins? (Round answer to one decimal place.) \[ \mu = \]2. **Standard Deviation:** Let \( X \) represent the number of games (out of 282) that you win. Find the standard deviation for the probability distribution of \( X \). (Round answer to two decimal places.) \[ \sigma = \]3. **Range Rule of Thumb:** The range rule of thumb specifies that the minimum usual value for a random variable is \( \mu - 2\sigma \) and the maximum usual value is \( \mu + 2\sigma \). You already found \( \mu \) and \( \sigma \) for the random variable \( X \). Use the range rule of thumb to find the usual range of \( X \) values. Enter answer as an interval using square-brackets and only whole numbers. \[ \text{usual values} = \]---This exercise involves calculating expected values and standard deviation, aiding in understanding the variability and typical outcomes in probability exercises.

The question is about discrete probability distributionGiven :Prob. of winning a game ( p ) =…

Answered: You are playing a card came, and the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Verify whether the given table represents a probability distribution. In those cases where a probability distribution is described, find the mean and standard deviation. NOTE: The Rounding Rule for the mean and standard deviation: They should be rounded to one more decimal place than occurs in the raw data. For a group of four students, the number y who takes the Calculus II class next semester is given by this table. y P(y) 0 0.5131 1 0.3139 2 0.0624 3 0.1102 4 0.2002 Probability distribution with μ=0.4 and σ=0.4 Probability distribution with μ=0.6 and σ=0.1 Probability distribution with μ=0.6 and σ=0.3 Probability distribution with μ=0.7 and σ=0.4
Assume you have a normal distribution representing the likelihood of project completion times. The mean of this distribution is 14, and the standard deviation is 4. The probability of completing the project in 15 or fewer days is: a. 0.59 b. 0.27 c. 0.93 d. 0.75
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