The system of first order differential equations has solution y₁(t) = Y₂ (t) = S3/1₁ 13/12 = 4 y₁ + 1 y2, -6 y₁ - 1 y2, y₁ (0) = 10 Y2 (0) = -10

Advanced Engineering Mathematics
10th Edition
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Chapter2: Second-order Linear Odes
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The system of first order differential equations
has solution
y₁ (t) =
=
y₂(t) =
3/₁
ly/2
=
4 y₁ + 1 y2,
-6 y₁ - 1 y2,
y₁ (0) = 10
Y₂ (0) = -10
Transcribed Image Text:The system of first order differential equations has solution y₁ (t) = = y₂(t) = 3/₁ ly/2 = 4 y₁ + 1 y2, -6 y₁ - 1 y2, y₁ (0) = 10 Y₂ (0) = -10
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