The system is released from rest with the cable taut. For the friction coefficients = 0.29 and = 0.22, calculate the acceleration of each body and the tension I in the cable. Neglect the small mass and friction of the pulleys.
The system is released from rest with the cable taut. For the friction coefficients = 0.29 and = 0.22, calculate the acceleration of each body and the tension I in the cable. Neglect the small mass and friction of the pulleys.
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![The system is released from rest with the cable taut. For the friction coefficients = 0.29 and 4 = 0.22, calculate the
acceleration of each body and the tension T'in the cable. Neglect the small mass and friction of the pulleys.
Ms. Hk.
28°
30 kg
A
B
45 kg
a of A = -1.693
Direction = Up the incline
a of B-3.387
Direction=Downward
T=
m/sec^2
m/sec^2
N
X) X\ х](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9de751ce-d0b4-477e-8168-a98ebf0c920e%2F7e8415b2-43f1-4ec7-9742-140dd178a4d8%2Fvvzdes_processed.png&w=3840&q=75)
Transcribed Image Text:The system is released from rest with the cable taut. For the friction coefficients = 0.29 and 4 = 0.22, calculate the
acceleration of each body and the tension T'in the cable. Neglect the small mass and friction of the pulleys.
Ms. Hk.
28°
30 kg
A
B
45 kg
a of A = -1.693
Direction = Up the incline
a of B-3.387
Direction=Downward
T=
m/sec^2
m/sec^2
N
X) X\ х
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