The system function H(z) of a stable LTI system has three poles and three zeros, as shown in the plot below. Also, the system response to the input x[n] = (-1)" (all n) is given by y[n] = 20(-1)" (all n). (М 3 2) z = 0 (M = 1) z = 1 z = -2 = 2) z = 1/2 а) Determine H(z) and its region of convergence. b) Determine the impulse response h[n]. c) Give one value of a (other than zero) for which the sequence x'[n] = a" (for all n) %3D is not an acceptable input for this system. 2)

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### Problem Statement

The system function \( H(z) \) of a stable LTI system has three poles and three zeros, as shown in the plot below. Also, the system response to the input \( x[n] = (-1)^n \) (for all \( n \)) is given by \( y[n] = 20 (-1)^n \) (for all \( n \)).

#### Pole-Zero Plot:
- Zeros:
  - \( z = -2 \) (multiplicity 2)
  - \( z = 0 \) (multiplicity 1)
- Poles:
  - \( z = 1 \) (multiplicity 1)
  - \( z = \frac{1}{2} \) (multiplicity 1)

This can be visually represented with the pole-zero plot:
- Zeros are marked with an "x".
- Poles are marked with a "o".

```plaintext
           (M = 1)
             o

                 -------------
                 |          |
                 x          o (M = 1)
           z = -2         z = 1/2
           (M = 2)

                 x
           z = 0
           (M = 2)
```

### Questions:

a) **Determine \( H(z) \) and its region of convergence.**

b) **Determine the impulse response \( h[n] \).**

c) **Give one value of \( a \) (other than zero) for which the sequence \( x'[n] = a^n \) (for all \( n \)) is not an acceptable input for this system.**

---

### Solutions:

**a) Determining \( H(z) \) and its region of convergence:**

The system function \( H(z) \) can be expressed as the ratio of the polynomial of zeros and the polynomial of poles.
Given the zeros and poles:

\[
H(z) = K \frac{(z+2)^2 z}{(z-1)\left(z-\frac{1}{2}\right)}
\]

where \( K \) is a constant to be determined using the given response.

**b) Determining the impulse response \( h[n] \):**

The impulse response \( h[n] \) is the inverse Z-transform of \( H(z) \).

**c) Finding a non-zero value of \( a \) for which
Transcribed Image Text:### Problem Statement The system function \( H(z) \) of a stable LTI system has three poles and three zeros, as shown in the plot below. Also, the system response to the input \( x[n] = (-1)^n \) (for all \( n \)) is given by \( y[n] = 20 (-1)^n \) (for all \( n \)). #### Pole-Zero Plot: - Zeros: - \( z = -2 \) (multiplicity 2) - \( z = 0 \) (multiplicity 1) - Poles: - \( z = 1 \) (multiplicity 1) - \( z = \frac{1}{2} \) (multiplicity 1) This can be visually represented with the pole-zero plot: - Zeros are marked with an "x". - Poles are marked with a "o". ```plaintext (M = 1) o ------------- | | x o (M = 1) z = -2 z = 1/2 (M = 2) x z = 0 (M = 2) ``` ### Questions: a) **Determine \( H(z) \) and its region of convergence.** b) **Determine the impulse response \( h[n] \).** c) **Give one value of \( a \) (other than zero) for which the sequence \( x'[n] = a^n \) (for all \( n \)) is not an acceptable input for this system.** --- ### Solutions: **a) Determining \( H(z) \) and its region of convergence:** The system function \( H(z) \) can be expressed as the ratio of the polynomial of zeros and the polynomial of poles. Given the zeros and poles: \[ H(z) = K \frac{(z+2)^2 z}{(z-1)\left(z-\frac{1}{2}\right)} \] where \( K \) is a constant to be determined using the given response. **b) Determining the impulse response \( h[n] \):** The impulse response \( h[n] \) is the inverse Z-transform of \( H(z) \). **c) Finding a non-zero value of \( a \) for which
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