The surface area of ​​each of the two opposite loaded conductive plates with equivalent properties is 2.50 cm2. The plates are separated by a dielectric material with a dielectric constant K = 3.60 and a thickness of 1.80 mm. The net electric field strength in the dielectric material is 1.20 ×1000000 V / m. Part A : Calculate the amount of load σ accumulated in unit area on the conductor plate. Part B :Calculate the magnitude of the surface charge density σ1 of the dielectric material. Part C:Find the total electric field energy U stored in the shawl.

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The surface area of ​​each of the two opposite loaded conductive plates with equivalent properties is 2.50 cm2. The plates are separated by a dielectric material with a dielectric constant K = 3.60 and a thickness of 1.80 mm. The net electric field strength in the dielectric material is 1.20 ×1000000 V / m.

Part A : Calculate the amount of load σ accumulated in unit area on the conductor plate.

Part B :Calculate the magnitude of the surface charge density σ1 of the dielectric material.

Part C:Find the total electric field energy U stored in the shawl.

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