The superintendent of a large school district, having once had a course in probability and statistics, believes that the number of teachers absent on any given day has a Poisson distribution with parameter u. Use the accompanying data on absences for days to obtain a 95% large-sample CI for u. Number of absences 0 1 2 3 4567 89 10 Frequency 147 11 9 6 6 221 1 [Hint: The mean and variance of a Poisson variable both equal u, so X- u VH/n has approximately a standard normal distribution. Now proceed as in the derivation of the interval for p by making a probability statement (with probability 1 - a) and solving the resulting inequalities for u.] (Round your answers two decimal places.
The superintendent of a large school district, having once had a course in probability and statistics, believes that the number of teachers absent on any given day has a Poisson distribution with parameter u. Use the accompanying data on absences for days to obtain a 95% large-sample CI for u. Number of absences 0 1 2 3 4567 89 10 Frequency 147 11 9 6 6 221 1 [Hint: The mean and variance of a Poisson variable both equal u, so X- u VH/n has approximately a standard normal distribution. Now proceed as in the derivation of the interval for p by making a probability statement (with probability 1 - a) and solving the resulting inequalities for u.] (Round your answers two decimal places.
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Chapter1: Starting With Matlab
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![The superintendent of a large school district, having once had a course in probability and statistics, believes that the number of teachers absent on any given day has a Poisson distribution with parameter \( \mu \). Use the accompanying data on absences for 50 days to obtain a 95% large-sample confidence interval for \( \mu \).
| Number of absences | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|--------------------|---|---|---|---|---|---|---|---|---|---|----|
| Frequency | 1 | 4 | 7 | 11| 9 | 6 | 6 | 2 | 2 | 1 | 1 |
*[Hint: The mean and variance of a Poisson variable both equal \( \mu \), so]*
\[
Z = \frac{\bar{X} - \mu}{\sqrt{\mu/n}}
\]
has approximately a standard normal distribution. Now proceed as in the derivation of the interval for \( p \) by making a probability statement (with probability \( 1 - \alpha \)) and solving the resulting inequalities for \( \mu \). *(Round your answers to two decimal places.)*
\[ \left( \boxed{\phantom{XXX}}, \boxed{\phantom{XXX}} \right) \]
**Explanation of the Data:**
- The table shows the frequency of teacher absences over 50 days.
- The number of absences ranges from 0 to 10.
- Each number of absences has a corresponding frequency indicating how many days that number of absences occurred.
**Statistical Note:**
- The approach uses a Poisson distribution where both the mean and variance are equal to \( \mu \).
- The standard normal distribution is used to derive the confidence interval.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa0bb33da-4292-4a51-8799-113a66f1981e%2Ff35bab81-11b1-4b23-8a65-4b92afb2eefa%2Fptiycuy_processed.png&w=3840&q=75)
Transcribed Image Text:The superintendent of a large school district, having once had a course in probability and statistics, believes that the number of teachers absent on any given day has a Poisson distribution with parameter \( \mu \). Use the accompanying data on absences for 50 days to obtain a 95% large-sample confidence interval for \( \mu \).
| Number of absences | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|--------------------|---|---|---|---|---|---|---|---|---|---|----|
| Frequency | 1 | 4 | 7 | 11| 9 | 6 | 6 | 2 | 2 | 1 | 1 |
*[Hint: The mean and variance of a Poisson variable both equal \( \mu \), so]*
\[
Z = \frac{\bar{X} - \mu}{\sqrt{\mu/n}}
\]
has approximately a standard normal distribution. Now proceed as in the derivation of the interval for \( p \) by making a probability statement (with probability \( 1 - \alpha \)) and solving the resulting inequalities for \( \mu \). *(Round your answers to two decimal places.)*
\[ \left( \boxed{\phantom{XXX}}, \boxed{\phantom{XXX}} \right) \]
**Explanation of the Data:**
- The table shows the frequency of teacher absences over 50 days.
- The number of absences ranges from 0 to 10.
- Each number of absences has a corresponding frequency indicating how many days that number of absences occurred.
**Statistical Note:**
- The approach uses a Poisson distribution where both the mean and variance are equal to \( \mu \).
- The standard normal distribution is used to derive the confidence interval.
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