The summary of a randomized block experiment with four groups and eight blocks is given below in the following ANOVA summary table. Complete parts (a) and (b). Degrees of Freedom Mean Square (Variance) MSA = 70 Source Sum of Squares SSA = 210 Among groups c-1=3 Among blocks r-1=7 FSTAT 5.4444 FSTAT =6.0 SSBL = 540 MSBL = 77.1429 Error Total (r- 1(c- 1) = 21 SSE = 270 rc-1= 31 MSE = 12.8571 SST= 1020 a. At the 0.05 level of significance, is there evidence of a difference among the four group means? Determine the null and alternative hypotheses. Let c represent the number of groups and r represent the number of blocks. Họ: H: Not all H are equal (where j= 1, 2, ., c) Not all H, are equal (where i= 1, 2, .., r)
The summary of a randomized block experiment with four groups and eight blocks is given below in the following ANOVA summary table. Complete parts (a) and (b). Degrees of Freedom Mean Square (Variance) MSA = 70 Source Sum of Squares SSA = 210 Among groups c-1=3 Among blocks r-1=7 FSTAT 5.4444 FSTAT =6.0 SSBL = 540 MSBL = 77.1429 Error Total (r- 1(c- 1) = 21 SSE = 270 rc-1= 31 MSE = 12.8571 SST= 1020 a. At the 0.05 level of significance, is there evidence of a difference among the four group means? Determine the null and alternative hypotheses. Let c represent the number of groups and r represent the number of blocks. Họ: H: Not all H are equal (where j= 1, 2, ., c) Not all H, are equal (where i= 1, 2, .., r)
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Problem 1P
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The summary of a randomized block experiment with four groups and eight
blocks is given below in the following ANOVA summary table. Complete parts (a)
A)At the 0.05 level of significance, is there evidence of a difference among the four group means? Determine the null and alternative hypotheses. Let c represent the number of groups and r represent the number of blocks
Transcribed Image Text:The summary of a randomized block experiment with four groups and eight blocks is given below in the following ANOVA summary table. Complete parts (a) and (b).
Degrees of
Freedom
Mean Square
(Variance)
Source
Sum of
F
Squares
SSA = 210
Among groups c-1=3
Among blocks r-1=7
FSTAT = 5.4444
FSTAT = 6.0
MSA = 70
SSBL = 540 MSBL = 77.1429
(г- 1/с - 1) %3 21
rc - 1=31
Error
SSE = 270
MSE = 12.8571
Total
SST = 1020
a. At the 0.05 level of significance, is there evidence of a difference among the four group means? Determine the null and alternative hypotheses. Let c represent the number of groups and r represent the number of blocks.
Но
Not all H; are equal (where j= 1, 2, ., c)
H1 = H2 = .. = Hc
H1 = H2 = ... = H.
Not all H; are equal (where i= 1, 2, .., r)
Transcribed Image Text:The summary of a randomized block experiment with four groups and eight blocks is given below in the following ANOVA summary table. Complete parts (a) and (b).
Degrees of
Freedom
Mean Square
(Variance)
Source
Sum of
F
Squares
SSA = 210
Among groups c-1=3
Among blocks r-1=7
FSTAT = 5.4444
FSTAT = 6.0
MSA = 70
SSBL = 540 MSBL = 77.1429
(г- 1/с - 1) %3 21
rc - 1=31
Error
SSE = 270
MSE = 12.8571
Total
SST = 1020
a. At the 0.05 level of significance, is there evidence of a difference among the four group means? Determine the null and alternative hypotheses. Let c represent the number of groups and r represent the number of blocks.
Но
Not all H; are equal (where j= 1, 2, ., c)
H1 = H2 = .. = Hc
H1 = H2 = ... = H.
Not all H; are equal (where i= 1, 2, .., r)
Expert Solution
Step 1
From the given information, total number of groups c = 4.
Total number of blocks r = 8.
The ANOVA Summary table is,
|
Source |
Degrees of freedom |
Sum of Squares |
Mean Square (Variance) |
F |
|
Among groups |
c – 1 = 3 |
SSA = 210 |
MSA = 70 |
FSTAT = 5.4444 |
|
Among blocks |
r – 1 = 7 |
SSBL = 540 |
MSBL = 77.1429 |
FSTAT = 6.0 |
|
Error |
(r – 1)(c – 1) = 21 |
SSE = 270 |
MSE = 12.8571 |
|
|
Total |
rc – 1 = 31 |
SST = 1020 |
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