The substance to be analyzed – is green colored, highly soluble in water salt. Dimethylglyoxime reaction gives pinky-red precipitate. After precipitation of cation by "sodium carbonate drawing out" method, supernatant was treated by silver nitrate solution in acid medium – appearance of white precipitate, which soluble in saturated ammonium carbonate solution, has been observed. What kind of substance is this? NiCl, MNSO4 CuCl, KBr

The substance to be analyzed – is green colored, highly soluble in water salt. Dimethylglyoxime reaction gives pinky-red precipitate. After precipitation of cation by "sodium carbonate drawing out" method, supernatant was treated by silver nitrate solution in acid medium – appearance of white precipitate, which soluble in saturated ammonium carbonate solution, has been observed. What kind of substance is this? NiCl, MNSO4 CuCl, KBr

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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13. Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphtholsulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-mL aliquot of the urine was treated with molybdate reagent and aminonaphtholsulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 0.205 1.00 ppm P 2.00 ppm P 3.00 ppm P 4.00 ppm P Urine sample 0.410 0.615 0.820 0.625 (a) Calculate the number of grams of phosphorus excreted per day. (b) Calculate the phosphate concentration in the urine as millimoles per liter. (c) Calculate the ratio of HPO,2- to H2PO4" in the sample: K, = 1.1 x 10-2; K2= 7.5 x 10-8; K3= = 4.8 x 10-13 %3D
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