The student newspaper at a large university asks an SRS of 250 undergraduates, "Do you favor eliminating the carnival from the term-end celebration?" All in all, 150 of the 250 are in favor. Suppose that (unknown to you) 55% of all undergraduates favor eliminating the carnival. If you took a very large number of SRSS of size n = 250 from this population, the sampling distribution of the sample proportion p would be exactly Normal with mean 0.55 and standard deviation 0.03. exactly Normal with mean 0.60 and standard deviation 0.03. heavily skewed with mean 0.55 and standard deviation 0.03. approximately Normal with mean 0.55 and standard deviation 0.03. approximately Normal with mean 0.60 and standard deviation 0.03.

MATLAB: An Introduction with Applications
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The student newspaper at a large university asks an SRS of 250 undergraduates, "Do you favor eliminating the carnival from the
term-end celebration?" All in all, 150 of the 250 are in favor. Suppose that (unknown to you) 55% of all undergraduates favor
eliminating the carnival.
If you took a very large number of SRSS of size n = 250 from this population, the sampling distribution of the sample
proportion p would be
exactly Normal with mean 0.55 and standard deviation 0.03.
exactly Normal with mean 0.60 and standard deviation 0.03.
heavily skewed with mean 0.55 and standard deviation 0.03.
approximately Normal with mean 0.55 and standard deviation 0.03.
approximately Normal with mean 0.60 and standard deviation 0.03.
Transcribed Image Text:The student newspaper at a large university asks an SRS of 250 undergraduates, "Do you favor eliminating the carnival from the term-end celebration?" All in all, 150 of the 250 are in favor. Suppose that (unknown to you) 55% of all undergraduates favor eliminating the carnival. If you took a very large number of SRSS of size n = 250 from this population, the sampling distribution of the sample proportion p would be exactly Normal with mean 0.55 and standard deviation 0.03. exactly Normal with mean 0.60 and standard deviation 0.03. heavily skewed with mean 0.55 and standard deviation 0.03. approximately Normal with mean 0.55 and standard deviation 0.03. approximately Normal with mean 0.60 and standard deviation 0.03.
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