The stress intensity factor for a partial-through thickness crack is given by where a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2
The stress intensity factor for a partial-through thickness crack is given by where a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
The stress intensity factor for a partial-through thickness crack is given by
where a is the length of of crack through a wall thickness t. If the crack is 10 mm
deep in a wall 20 mm thick determine whether the wall will support a stress of 190
MPa if it is made from steel with fracture toughness of 30 MPA m1/2
![**Q5. The stress intensity factor for a partial-through thickness crack is given by**
\[ K = \sigma \sqrt{\pi a} \sqrt{\sec \frac{\pi a}{3t}} \]
- **Explanation:**
- \( K \) is the stress intensity factor.
- \( \sigma \) represents the applied stress.
- \( a \) is the crack length.
- \( t \) is the thickness of the material.
- The expression involves a square root and a trigonometric secant function, indicating that the stress intensity factor depends on geometric and material properties.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08a0d1a7-4387-4b00-bd8e-a511cc6565f1%2Fb7702ea5-eccc-4490-851d-438a6ec43876%2Fobx5n7m_processed.png&w=3840&q=75)
Transcribed Image Text:**Q5. The stress intensity factor for a partial-through thickness crack is given by**
\[ K = \sigma \sqrt{\pi a} \sqrt{\sec \frac{\pi a}{3t}} \]
- **Explanation:**
- \( K \) is the stress intensity factor.
- \( \sigma \) represents the applied stress.
- \( a \) is the crack length.
- \( t \) is the thickness of the material.
- The expression involves a square root and a trigonometric secant function, indicating that the stress intensity factor depends on geometric and material properties.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY