The stress intensity factor for a partial-through thickness crack is given bywhere a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2 **Q5. The stress intensity factor for a partial-through thickness crack is given by**\[ K = \sigma \sqrt{\pi a} \sqrt{\sec \frac{\pi a}{3t}} \]- **Explanation:** - \( K \) is the stress intensity factor. - \( \sigma \) represents the applied stress. - \( a \) is the crack length. - \( t \) is the thickness of the material. - The expression involves a square root and a trigonometric secant function, indicating that the stress intensity factor depends on geometric and material properties.

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The stress intensity factor for a partial-through thickness crack is given by where a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2

The stress intensity factor for a partial-through thickness crack is given by where a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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